Outputting Current Time in C++

I was wondering how to output the current time in C++... Specifically, I'd like to print the time in this format:

Code:

02:56:32:231
//where hh:mm:ss:MMM, hh = hours, mm = mins, ss = seconds, MMM = milliseconds

I know that there are functions time, ctime, and others, but they are quite confusing. I was wondering if an elite C++ programmer knew the best/easiest way to present the current time of day in that format.

Thanks for your help!

So far I have this as a beta:

Code:

time_t now;
struct tm *current;
now = time(0);
current = localtime(&now);
cout << "hour: " << current->tm_hour << endl;
cout << "mins: " << current->tm_min << endl;
cout << "sec: " << current->tm_sec << endl;

which outputs (if the time is 5:53:43PM)

Code:

hour: 17
mins: 53
sec: 43

So how would I get the milliseconds?

For future reference to anyone who might need this, I have figured it out:

Code:

time_t now;
struct tm *current;
now = time(0);
current = localtime(&now);
cout << "hour: " << current->tm_hour << endl;
cout << "mins: " << current->tm_min << endl;
cout << "sec: " << current->tm_sec << endl;

struct timeval detail_time;
gettimeofday(&detail_time,NULL);
cout << "milli: " << detail_time.tv_usec/1000 << endl;

This will output (if the time is 6:05:53PM)

Code:

hour: 18
mins: 5
sec: 53
milli: 707
//sec and millisec WILL change obviously

SeeForever: Learn and know that gettimeofday and the structs it works with well my friend; when you get to timewait mutex etc locks (try for x milliseconds to lock this resource; if no luck, give me a timeout signal) you will be glad that you did. What is surprisingly hard is implementing gettimeofday() (so it is POSIX compliant) on other platforms...