deleting parts of a string

I'm trying to get my program to go through the string typed in by the user and strip it of EVERYTHING but the numbers. I can't place my finger on what I'm missing. Help please?

Code:

#include<iostream>
#include<string>
using namespace std ;

int main()
{
	string myString ;

	cout << "Please enter string/numbers: " ;
	
	getline( cin, myString ) ;

	// disgard anything that's not an int
	for ( int x = 0 ; x < 10 ; x++ )
	if ( !isdigit( myString[ x ] ) )
		myString.erase( x, 1 ) ;

	// display contents
	cout << myString << endl ;
} // end main

Are you sure every string that a user types in is going to be exactly 10 characters long?

That's another thing... when I make the number greater than 10 (say 15) I get an error when I try to enter anything into the program at runtime...

Well, aside from needing to use the .length() operator (or another method entirely), what exactly is it not doing that you need it to do?

Hmmm... I tried the .length as you suggested, but still get the runtime error... I'm trying to make sure that the user doesn't enter any data other than numbers.

Code:

#include<iostream>
#include<string>
using namespace std ;

int main()
{
	string myString ;

	cout << "Please enter string/numbers: " ;
	
	getline( cin, myString ) ;

	// disgard anything that's not an int
	for ( int x = 0 ; myString.length() ; x++ )
	if ( !isdigit( myString[ x ] ) )
		myString.erase( x, 1 ) ;

	// display contents
	cout << myString << endl ;
} // end main

What do you think happens to the string when you erase a character from it?

sounds to me like you need to create a way to block all input except numbers from being entered, have you tried using a

Code:

if(cin.fail==1){}

which will trigger if any letter is used to represent a number (such as typing "seven" instead of "7")?

another possible option would be to to use the pop_back() function, however u would have to swap the value u want to get rid of with the last value, then resort, if the list was sorted