Thread: Simple while loop

  1. #1
    Registered User
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    Angry Simple while loop

    Sorry to be wasting your time with this simple problem, but I'm in my first class and am stumped on a while loop.

    Here is what I have:


    Code:
    #include <iostream> 
    int main() {
       int i = 100;
     
          
        while (i <= 150){
          cout << i << " ";
           i = i + 2;}
          
    return 0;}


    The program runs just fine, but the numbers all appear on one line. I need to have only 6 per line, for example 100 102 104 106 108 110
    112 114 116 etc.... to 150

    Keep in mind I have to use a while loop. I know I need to add another variable somewhere in that loop but I cant figure out the syntax I need to use. Can someone give me a push in the right direction? Thank you very much.

  2. #2
    Registered User claudiu's Avatar
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    First of all this is C++ not C, so please post under the appropriate forum. Admins will probably move the thread there.

    Secondly, all you need is another variable, let's call it x that you initialize to 0 before the loop. Then, inside the loop you increment and test if it's new value % 6 == 0. That means that the variable value has reached a value which is a multiple of 6 and it's time to print an endline:

    i.e. cout << endl;

  3. #3
    C++ Witch laserlight's Avatar
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    Oh yes, so I have moved it.
    Quote Originally Posted by Bjarne Stroustrup (2000-10-14)
    I get maybe two dozen requests for help with some sort of programming or design problem every day. Most have more sense than to send me hundreds of lines of code. If they do, I ask them to find the smallest example that exhibits the problem and send me that. Mostly, they then find the error themselves. "Finding the smallest program that demonstrates the error" is a powerful debugging tool.
    Look up a C++ Reference and learn How To Ask Questions The Smart Way

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