Memory Game!

Hi~~~ I am doing my computer project.......
and...I need your help!
this computer project is about "Memory Game"

this is following:

There are 20 cards. Each card has a number between 1- 10
each numbers occurs twice. Look at two cards,if they are the same, they are marked as taken. Game goes on until all cards are marked as taken

e.g of output:

"Enter two cards to be looked at:" // then user put 2 numbers

3,5

"card 3 has value of 7"
"card 5 has value of 6"


"Enter two cards to be looked at:"//user put 2 numbers again
3,6

"Both cards have value of 7,You found a pair!"

"Enter two cards to be looked at:"//user put 2 numbers again
3,4

"card 3 was already turned out!"



Please give me a solution..............

First, you need a structuce:

Code:

struct Card
{
    int number, value;
    bool found;
};

And initialization:

Code:

Card deck[20];
for(int i = 0;  i < 20;  i++)
{
    deck[i].found = 0;
    deck[i].number = i;
    if(i < 10)
        deck[i].value = i+1;
    else
        deck[i].value = i+1-10;
}

Perhaps a shuffle:

Code:

Card temp;
int swap;
for(int i = 0;  i < 123;  i++)
{
    temp = deck[rand()%20];
    for(;;)
    {
        i = rand()%20;
        if(i != swap.number)
            break;
    }
    deck[temp.number] = deck[swap];
    deck[swap] = temp;
}

(write in a hurry - beware of errors!)

Now just flag the cards that have been found and compare the values to find a pair.

Code:

get input to a and b
if((deck[a].value == deck[b].value) && (deck[a].found = 0))
{
    Match found!
    deck[a].found = deck[b].found = 1;
}

And for a final check

Code:

int i;
for(i = 0;  i < 20;  i++)
    if(deck[i].found == 0)
        break;
if(i == 19)
    all cards found