Need help looping this switch statement

Hey guys I'm wondering how to loop the default at the end of the switch. I'm doing this so it will obviously have me go back and answer with 1, 2 or 3 again thanks.

Code:

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#include <iostream>
              using namespace std;


            int main()
        {
              int myAnswer, i;


              cout << "In what country is Wagga Wagga?" << endl;
              cout << "1: Japan" << endl;
              cout << "2: Australia" << endl;
              cout << "3: Israel" << endl;
              cin >> myAnswer;
           
            switch (myAnswer)
                  {
                    case 1:
                    cout << "Incorrect" << endl;
                    break;
               
                case 2:
              cout << "Correct" <<endl;
              break;
             
              case 3:
              cout << "Incorrect" << endl;
              break;
              default:
              cout << "Please enter 1 2 or 3 for your answer" << endl;

}
 
 system ("pause");
 
 return 0;
 
}

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please excuse how messy it looks but im in a hurry thanks

Code:

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do
{
    /* something over and over */
}while(  /* user input is not 1,2,or 3 */ );

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would be one approach

Quote:

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Originally Posted by QuestionKing

Code:

---

do
{
    /* something over and over */
}while(  /* user input is not 1,2,or 3 */ );

---

would be one approach

---

No matter how many different variations of that i try to use, it won't work. Any other/more advice?

BTW- I'm not doing this for class or anything like that, actually doing it for someone else, so feel free to post the code if you want. thanks guys

Quote:

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Originally Posted by nick753

No matter how many different variations of that i try to use, it won't work. Any other/more advice?

BTW- I'm not doing this for class or anything like that, actually doing it for someone else, so feel free to post the code if you want. thanks guys

---

If you want more specific help you need to give more specific information about the problem. For example, give in code what one of the variations you tried that didn't work and what about it didn't (work)?

Code:

---

bool done = false;

while(!done)
{
      cout << "In what country is Wagga Wagga?" << endl;
      cout << "1: Japan" << endl;
      cout << "2: Australia" << endl;
      cout << "3: Israel" << endl;
      cin >> myAnswer;
           
      switch (myAnswer)
      {
            case 1:
                cout << "Incorrect" << endl;
                done = true;
                break;
               
            case 2:
                cout << "Correct" <<endl;
                done = true;
                break;
             
            case 3:
                cout << "Incorrect" << endl;
                done = true;   
                break;
           
            default:
                cout << "Please enter 1 2 or 3 for your answer" << endl;

}

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Thanks x4xlds, Can you please explain a little about what done and (!done) and the done = true means? I'd appreciate it. thanks

Saying !done is the same as saying while(done == false) . You set done to true when you have met the requirements to end the loop, in your case a valid answer of 1,2 or 3.

Quote:

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Originally Posted by xds4lx

Saying !done is the same as saying while(done == false) . You set done to true when you have met the requirements to end the loop, in your case a valid answer of 1,2 or 3.

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Hmm okay thanks.. got any good sites to look up the done statement on?

google c++ not operator

Quote:

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Originally Posted by QuestionKing

google c++ not operator

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Are you talking about the (!done)? I know what that means i just don't know what the done = false and done = true means

Code:

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done = false;  //  sets the boolean value of the variable done equal to false

done = true;  //  sets the boolean value of the variable done eaual to true

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google boolean

True and false can also be thought as 1 (for true) and 0 for false.

The basic boolean operators are AND (&&), OR (||), NOT (!). Consider the following truth-tables:
(C is the result of the operation).
AND:
A 0 1 0 1
B 0 0 1 1
C 0 0 0 1

OR:
A 0 1 0 1
B 0 0 1 1
C 0 1 1 1

NOT:
A 0 1
C 1 0

Now, say you have two 8-bit numbers:

1010 1010 and
0101 0101

ANDing them together is very straight forward. 0 && 1 = 0, 1 && 1 = 1.
That gives:

0000 0000 as the result.
ORing them gives 1111 1111.

It's also very important to know that every conditional expression IS evaluated to either True or False.

Consider this:

int i = 7;
int a = 5;
while(i=>a)
{
}

The result of the "i=>a" will be evaluated, and either the expression is True, or it is False. It can't be "half true".

Thanks guys. I knew most of that but just didn't understand the done statement.