Pointer to a class array?

Peacelyk · 01-13-2010, 06:37 AM

Ok, i need some explanation:

Code:

MyClass *Human[10][10];

what does it mean? a pointer to a MyClass array?
one interesting thing is that i'm able to do that:

Code:

for (unsigned int uiRow = 0; uiRow < 10; ++uiRow) {
			for (unsigned int uiCol = 0; uiCol < 10; ++uiCol) {
				Human[uiRow][uiCol]	= 0;
			}
		}

but when i tryed this:

Code:

int *numbers[10][10];

for(int i=0;i<10;i++){
        for(int j=0;j<10;j++){
            numbers[i][j] = i*j;
        }
    }

I get an error: invalid conversion from "int" to "int*"
Any help?

anon · 01-13-2010, 06:42 AM

It is an array of pointers. You can set a pointer to 0 (NULL).

Peacelyk · 01-13-2010, 06:59 AM

Ok, but what's this then:

Code:

int main(int argc, char *argv[])

array of pointers to char?
And yet we are able to get out of it main function arguments.

I thought that

Code:

char *argv[]

is a pointer to a char array, which is pointer to pointer.

01-13-2010, 06:37 AM	#1
Peacelyk Registered User Join Date: Jan 2010 Posts: 4	Pointer to a class array? Ok, i need some explanation: Code: MyClass Human[10][10]; what does it mean? a pointer to a MyClass array? one interesting thing is that i'm able to do that: Code: for (unsigned int uiRow = 0; uiRow < 10; ++uiRow) { for (unsigned int uiCol = 0; uiCol < 10; ++uiCol) { Human[uiRow][uiCol] = 0; } } but when i tryed this: Code: int numbers[10][10]; for(int i=0;i<10;i++){ for(int j=0;j<10;j++){ numbers[i][j] = ij; } } I get an error: invalid conversion from "int" to "int" Any help?
Peacelyk is offline

01-13-2010, 06:59 AM	#3
Peacelyk Registered User Join Date: Jan 2010 Posts: 4	Ok, but what's this then: Code: int main(int argc, char argv[]) array of pointers to char? And yet we are able to get out of it main function arguments. I thought that Code: char argv[] is a pointer to a char array, which is pointer to pointer.
Peacelyk is offline

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