Error in passing arguments

This is a discussion on Error in passing arguments within the C++ Programming forums, part of the General Programming Boards category; I have defined an abstract class so I must use reference to that class... I also use a list with ...

  1. #1
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    Error in passing arguments

    I have defined an abstract class so I must use reference to that class... I also use a list with that type... the problem is when I intent to use the iterator as an argument to a function.
    This is the snap:
    Code:
     void sustituir(CTermino *&termino)
          //Dado un termino, le aplica la sustitución y lo entrega modificacdo
          {
              Parser parser;
            if (!(invalida) && !(esSustitucionVacia()))
            {
             //Solicito la lista de parametros del termino, para atenderlo en caso de que sea una funcion
             list<CTermino> * listaParametros = termino->getListaParametros();
             list<CTermino>::iterator it = listaParametros->begin();
             
    
             //Dependiendo del tipo de termino que sea, lo sustituyo         
             switch (!(termino->perteneceVariable(termino) || parser.esConstante(termino->getSimbolo()))) {
                case false:
                          if ( mapaReemplazos.find(termino->getSimbolo()) != mapaReemplazos.end())
                          { 
                            termino = (mapaReemplazos[termino->getSimbolo()]).second;
                          }           
                    break;
                case true:
                          while (it != listaParametros->end()) 
                          {
                            sustituir (*it);
                         
                            it++;  
                          }
                          termino->setListaParametros(*listaParametros);
                      break;     
                default: ;
                }
             delete listaParametros;             
            }
          }
    When I compile I got:
    error: no matching function for call to 'CSustitucion::sustituir(CTermino&)'
    note: candidates are: void CSustitucion::sustituir(CTermino*&)

    Is it possible to do what I intent to do? What should I do in order to correct such compile error?

    Thanks in advance!!!!!

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    error: no matching function for call to 'CSustitucion::sustituir(CTermino&)'
    note: candidates are: void CSustitucion::sustituir(CTermino*&)
    That error message means that you don't have a function called CSustitucion::sustituir that takes a CTermino reference as a parameter. Instead, it would appear you're instead passing a reference to a pointer? . . . can I see the code for CSustitucion::sustituir()?
    -- strange

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    Thats the code... its recursive function.

  4. #4
    C++ Witch laserlight's Avatar
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    Perhaps you should have called it as:
    Code:
    sustituir(&*it);
    since you need to pass a pointer according to the function signature.
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    I have also tried that alternative as I did in another case... but I dont know why it doesnt work... I intented to do a cast to, but I couldnt solve the issue.

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    *sigh*. I'm sorry, I'm very tired at the moment. I would concur with laserlight, that you need to pass it a pointer, since that is what the implementation specifies.

    Out of curiosity, why are you passing a reference to a pointer? Unless you're changing what the pointer references, it's slightly redundant . . . I think . . .
    -- strange

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    CTermino is an abstract class, thats what I use CTermino *

  8. #8
    C++ Witch laserlight's Avatar
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    Quote Originally Posted by tommantonela
    I have also tried that alternative as I did in another case... but I dont know why it doesnt work... I intented to do a cast to, but I couldnt solve the issue.
    Oh yes, that would not work, and that is directly related to what strange found strange.

    The problem is that since the parameter is a non-const reference, one must pass a modifiable lvalue to it. However the result of the address-of operator is an rvalue.

    You appear to need to pass the pointer by reference because of this statement:
    Code:
    termino = (mapaReemplazos[termino->getSimbolo()]).second;
    I have no understanding of what your code actually does, but perhaps you should pass the pointer by value and change the above statement to copy a CTermino object:
    Code:
    *termino = *(mapaReemplazos[termino->getSimbolo()]).second;
    By the way, please translate your code to English before posting. It makes it easier for most of us to understand your code.
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  9. #9
    Super Moderator VirtualAce's Avatar
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    By the way, please translate your code to English before posting. It makes it easier for most of us to understand your code.
    Seconded. I cannot tell from the code why you need to pass in *&CTermino or why single indirection (just a simple pointer) would not work just as well.

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    Algorithm Dissector iMalc's Avatar
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    switching on a bool is truly weird. Especially the default case for neither true or false. A Tri-bool perhaps?
    Most people use an if-else-statement.
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    Sorry for my Spanish Code!!! That function is used in order to solve a part of problems related with First Order Logic... to check the satisfiability of a set of clauses...
    The switch is not the problem even though is not the perfect solution...
    laserligth, I did what you said but the problem continuos :S

  12. #12
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    I am a little puzzled though. If CTermino is an abstract base class, then how can you have a list<CTermino>?
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  13. #13
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    Quote Originally Posted by strange View Post
    That error message means that you don't have a function called CSustitucion::sustituir that takes a CTermino reference as a parameter. Instead, it would appear you're instead passing a reference to a pointer? . . . can I see the code for CSustitucion::sustituir()?

    Unless I am overlooking/simplifying this but the error alone, really, points out the problem. . It specifies the possible candidate that matches your declaration, the compiler is trying to guess on your intentions here.

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