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Old 12-05-2009, 03:50 AM   #1
beginner for now
 
Join Date: Oct 2009
Posts: 33
rune tipe error - calculator

hi everybody I got an rune tip error -- >> it's marked in program
what should I do that program will give me one more time to correct if I want
manual or blind or exit calc

Code:
#include <iostream>
#include <string>
using namespace std;

void options (int * ptrchoose_calc);
void calc_manual ();
void calc_blind  ();


int main ()
{
    
    int choose_calc;
    int * ptrchoose_calc = &choose_calc;
    
    bool menu = true;
    do
    {
        cout << "\n                               CALCULATOR\n\n";
        
        cout << "choose\n'manual' calculator or\n'blind' calculator or\n'exit' calculator";
        options  (ptrchoose_calc);
        if       (choose_calc == 1) calc_manual();
        else if  (choose_calc == 2) calc_blind ();
        else if  (choose_calc == 3) menu = false;
///*error 999*/
        else {cout << "error 999";system ("pause");return 0;} // it shouldn't happen but as an safety procedure (emargency shut down)
/*error 999*///
    }
    while (menu == true);
    cout << "enter something to exit" << endl;
    int quit;
    cin >> quit;
    return 0;
}










////////////////////////////////////////////////////////////
void options (int * ptrchoose_calc)                       //
{                                                         //
     string y;                                            //
     string manual = "manual" ;                           //
     string blind  = "blind"  ;                           //
     string exit   = "exit"   ;                           //
                                                          //>>>>> UNKNOWN RUNE TIPE ERROR <<<<<  //
     getline (cin , y);                                   //             DESCRIPTION             //
                                                          //when it's on end of loop and comes   //I'm out of idea how to repair this
     if      (y == manual) * ptrchoose_calc = 1;          //back here it don't wont to ask for   //
     else if (y == blind)  * ptrchoose_calc = 2;          //        me to tipe in y again        //
     else if (y == exit)   * ptrchoose_calc = 3;          //
     else {cout << "please tipe in 'manual' or 'blind'";} //
}///////////////////////////////////////////////////////////

void calc_manual ()
{
     float number1    = 0  ;
     float number2    = 0  ;
     char operator1 = 0  ;
     
     cout << "\n\n\nenter a number:";
     cin >> number1;
     cin.clear();
     
     do
     {
         cout << "\nenter a operator + or - or / or * :";
         cin >> operator1;
     }
     while (operator1 != '+' && operator1 != '-' && operator1 != '/' && operator1 != '*');
     
     cout << "\nenter secon'd number:" ;
     cin >> number2;
     cin.clear();
     
     if      (operator1 == '+') cout << number1 << " + " << number2 << " = " << number1 + number2 << endl ;
     else if (operator1 == '-') cout << number1 << " - " << number2 << " = " << number1 - number2 << endl ;
     else if (operator1 == '/') cout << number1 << " / " << number2 << " = " << number1 / number2 << endl ;
     else if (operator1 == '*') cout << number1 << " * " << number2 << " = " << number1 * number2 << endl ;
///*error119*/
     else {cout << "error 119"; system ("pause");} // it shouldn't come to this
/*error119*///
}
void calc_blind  ()
{
     float number1    = 0  ;
     float number2    = 0  ;
     char operator1 = 0  ;
     
     cin >> number1;
     cin.clear();
     
     do
     {
         cin >> operator1;
         if (operator1 != '+' && operator1 != '-' && operator1 != '/' && operator1 != '*') cout << "please enter + or - or / or *" << endl;
     }
     while (operator1 != '+' && operator1 != '-' && operator1 != '/' && operator1 != '*');
     
     cin >> number2;
     cin.clear();
     
     if      (operator1 == '+') cout << number1 << " + " << number2 << " = " << number1 + number2 << endl ;
     else if (operator1 == '-') cout << number1 << " - " << number2 << " = " << number1 - number2 << endl ;
     else if (operator1 == '/') cout << number1 << " / " << number2 << " = " << number1 / number2 << endl ;
     else if (operator1 == '*') cout << number1 << " * " << number2 << " = " << number1 * number2 << endl ;
///*error229*/
     else {cout << "error 229"; system ("pause");} // it shouldn't come to this
/*error229*///
}
military genius is offline   Reply With Quote
Old 12-05-2009, 05:56 AM   #2
beginner for now
 
Join Date: Oct 2009
Posts: 33
problem solved
Code:
cin.ignore();
after
Code:
cin >> x
military genius is offline   Reply With Quote
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