how do you avoid using one function

This is a discussion on how do you avoid using one function within the C++ Programming forums, part of the General Programming Boards category; this is my code Code: #include <iostream> #include <cmath> using namespace std; float number1()//the function that gets the first number ...

  1. #1
    Registered User
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    Nov 2009
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    151

    how do you avoid using one function

    this is my code

    Code:
    #include <iostream>
    #include <cmath>
    
    using namespace std;
    
    float number1()//the function that gets the first number
    {
    	float x;
    
    	cout<<"please enter a number:";
    	cin>> x;//this is where the number is stored
    
    		return x;//the value of x is now "float number1()"
    }
    char operation()
    {
    	char a;
    
    	cout<<"please enter a operation (x, / , - , +, ^, s(square root for first number))";
    
    		cin>> a;
    	return a;
    }
    float number2()
    {
    	float y;
    
    	cout<<"please enter another number:";
    		cin>> y;
    
    		return y;
    }
    float math()
    {
    	float x = number1();//saying the variable x is the function "float number1()"
    	char a = operation();
        float y = number2();
        float answer;
    	float answer2;
    //this next part decides if you add, multiply, divide, or subtract depending on the input
    	switch(a)
    	{
    	case 'x':
    			answer = x*y;
    			break;
    
    	case '/':
    				answer = x/y;
    				break;
    
    	case '+':
    					answer = x+y;
    					break;
    
    	case '-':
    						answer = x-y;
    						break;
    	case '^'://pow is power (like 1 to the tenth power)
    		answer = pow (x,y);
    		break;
    	
    	case 's'://sqrt is square root
    		answer = sqrt (x);
    		break;
    		
    	}
    
    	return answer;
    }
    int main()
    {
    	float answer = math();
    	char enter;
    
    	cout<< answer <<"\n";
    	system("pause");
    
    
    	cin.get();
    }
    so i would like to know how to not do float number 2 when the operation is square root.

  2. #2
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    Oct 2009
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    48
    Just make the switch statement in math look like so:
    Code:
    switch(a)
    	{
    	case 'x':
                            float y = number2();
    			answer = x*y;
    			break;
    
    	case '/':
    		        float y = number2();
                            answer = x/y;
    			break;
    
    	case '+':
                            float y = number2();
    			answer = x+y;
    			break;
    
    	case '-':
                            float y = number2();
                 		answer = x-y;
    			break;
    
    	case '^'://pow is power (like 1 to the tenth power)
                            float y = number2();
            		answer = pow (x,y);
    	        	break;
    	
    	case 's'://sqrt is square root
    		answer = sqrt (x);
    		break;
    		
    	}

  3. #3
    Registered User
    Join Date
    Nov 2009
    Posts
    151
    i did that in a way but it didn't compile so i made it like this
    Code:
    if (a == 's'){
    		answer = sqrt (x);
    	}
    float y;
        switch (a){
    	case 'x':
    		y = number2();
    		answer = x*y;
    		break;
    	case '/':
    		y = number2();
    		answer = x/y;
    		break;
    	case '+':
    		y = number2();
    		answer = x+y;
    		break;
    	case '-':
    		y = number2();
    		answer = x-y;
    		break;
    	case '^':
    		y = number2();
    		answer = pow (x,y);
    		break;
    	}
    Last edited by bijan311; 11-21-2009 at 09:09 PM.

  4. #4
    Registered User
    Join Date
    Jan 2005
    Posts
    7,338
    You're close with that if, but I would put something else in an if. Notice how you're repeating the code to call number2()? Instead of putting that call in switch, put that in some sort of if control.

  5. #5
    The larch
    Join Date
    May 2006
    Posts
    3,573
    Code:
    if (is_binary_operation(a)) {
         float y = get_number("Enter another number: ");
         switch over binary operations
    }
    else {
        switch over unary operations
    }
    I might be wrong.

    Thank you, anon. You sure know how to recognize different types of trees from quite a long way away.
    Quoted more than 1000 times (I hope).

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