Ofstream parameter problem.

This is a discussion on Ofstream parameter problem. within the C++ Programming forums, part of the General Programming Boards category; Hi there, I am trying to allow a user to choose the filename for a file which will hold data. ...

  1. #1
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    Ofstream parameter problem.

    Hi there,

    I am trying to allow a user to choose the filename for a file which will hold data.

    The data will be entered into the file with ofstream.


    I started with this in my program:

    Code:
    char fileName[20];        //NO BOUNDS CHECKING!!!!
    cout << "Enter the name of the .csv file" << endl;
    cin >> fileName;
    ofstream streamname(fileName);
    Since there is no bounds checking, I tried to use a string:

    Code:
    string fileName;
    cout << "Enter the name of the .csv file" << endl;
    getline (cin, fileName);
    ofstream streamname(fileName);
    But (unless I was mistaken?) it seems ofstream cannot accept a string as a parameter.

    So I tried this:

    Code:
    string tempfilename;
    vector<string>fileName;
    cout << "Enter the name of the .csv file" << endl;
    getline (cin, tempfilename);
    fileName.push_back(tempfilename);
    ofstream streamname(fileName);
    But then Visual Studio reports:
    cannot convert parameter 1 from 'std::vector<_Ty>' to 'const char *'
    Could anyone advise me on how do this is as simply as possible?

    Thanks for any help!

  2. #2
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    Code:
    string fileName;
    cout << "Enter the name of the .csv file" << endl;
    getline (cin, fileName);
    ofstream streamname(fileName.c_str());
    bit∙hub [bit-huhb] n. A source and destination for information.

  3. #3
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    Hey thanks bithub!

    reading up on this, it converts the string to a c-style string, hence the error of "to 'const char *' "

    Great to learn this.

    Thanks buddy

  4. #4
    Registered User hk_mp5kpdw's Avatar
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    IIRC, this issue should be fixed in the near future.
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