class call to constructor

What does it mean to modify the class call to constructors, when I have the following situation:

class B and C inherits from A, class D inherit from B and C. A has a variable that is declared as public called count.

D calls the non-default constructor of it's of the ancestor

Quote:

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Originally Posted by -EquinoX-

What does it mean to modify the class call to constructors, when I have the following situation:

class B and C inherits from A, class D inherit from B and C. A has a variable that is declared as public called count.

D calls the non-default constructor of it's of the ancestor

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Well, since that's a diamond inheritance, the base A object will be double-constructed unless you specify the inheritance as virtual. Beyond that I don't know what you mean.

it means that D passes an argument in its constructor calls to its ancestors.

e.g:

Code:

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class A
{
  public:
  int count;
  A():count(0){} // <- default constructor (no arguments passed)
  A(int _count):count(_count){} // <- non default constructor
};

class B : public A
{
  B():A(){}
  B(int _count):A(_count){}
};

class C : public A
{
  C():A(){}
  C(int _count):A(_count){}
};

class D : public B,public C
{
  public:
  D(): B(1), C(2) {}
}

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