Thread: Listing factors in a grid.

Currently, I'm attempting to output the factors of a number in a grid format as opposed to just a direct line of numbers.

I am trying to use a for loop to accomplish this, however, i'm having a difficult time deducting a formula to create this.

Any input on how to make the output into a grid would be awesome. Thanks.

Code:

for(i=1;i<=n;i++)
		{
		   if(n%i==0)
		   cout << n/i <<endl;		
		}

What do you mean by grid format? How do you want your grid to look?

Say n=64

64 32 16 8 4
2 1

instead of

64
32
16
8
4
2
1

So if you just want a line break after every n numbers, then print a line break after every n numbers. (Use a counter to count how many you've printed on the current line, and when you reach the max print a new line and start over.)

Thanks. How many for loops would I need to go about doing that?

No special for loops other than the one you've already got that's printing all the numbers.

thank you! got it to work using a while statement as a counter, and I replaced the endl; statement in there.