Returning a class

I have a find function to a find a name and then return a class. I will show you parts i think you will need to help me.

In main()

Code:

list	*wineries = new list();
	winery	*wPtr;

wineries->insert(winery("Lopez Island Vinyard", "San Juan Islands", 7, 95));
wineries->insert(winery("Gallo", "Napa Valley", 200, 25));
wineries->insert(winery("Cooper Mountain", "Willamette Valley", 100, 47));



cout << "\n+++ list by rating\n";
	wineries->displayByRating(cout);

	cout << "\n>>> search for \"Gallo\"\n\n";
	wPtr = wineries->find("Gallo");                      // Where my problem lies
	if (wPtr != 0)
		cout << wPtr;
	else
		cout << "not found" << endl;

	cout << "\n>>> search for \"No Such\"\n\n";
	 wPtr = wineries->find("No Such");
	if (wPtr != 0)
		cout << wPtr;

Code:

winery * const list::find(const char * const name) const
{
	
node * curr;

winery	*wPtr;
	
	//wPtr = NULL;
	for(curr=headByName; curr; curr=curr->nextByName)
	{
		if(strcmp(curr->item.getName(), name) == 0)
		{
             wPtr = curr->item;                                           // causing error
			
		return wPtr;
		}
	}

Code:

#ifndef _WINERY_
#define _WINERY_

#include <ostream>

class winery
{
public:
	winery(const char * const name, const char * const location, const int acres, const int rating);
	virtual ~winery(void);
	const char * const getName() const;
	const char * const getLocation() const;
	const int getAcres() const;
	const int getRating() const;

	// display headings for lists of wineries
	static void displayHeadings(std::ostream& out);

	friend std::ostream& operator<<(std::ostream& out, winery *w);

private:
	char	*name;
	char	*location;
	int		acres;
	int		rating;
};

#endif // _WINERY_

Code:

#ifndef _LIST_
#define _LIST_

#include <ostream>
#include "winery.h"

using namespace std;

class list
{
public:
	list(void);				// constructor
	virtual ~list(void);	// destructor
	void displayByName(ostream& out) const;
	void displayByRating(ostream& out) const;
	void insert(const winery& winery);
	winery * const find(const char * const name) const;
	bool remove(const char * const name);

private:
	struct node
	{
		node(const winery& winery);		// constructor
		winery item;
		node * nextByName;
		node * nextByRating;
	};

	node * headByName;
	node * headByRating;
};

#endif // _LIST_

Error i get: error C2440: '=' : cannot convert from 'winery' to 'winery *'
I dont know how else to do this?

I dont know why the code dont line up better i have it VS set to tab 4
Thank you

Originally Posted by mrsirpoopsalot

Code:

winery * const list::find(const char * const name) const
{
	
node * curr;

winery	*wPtr;
	
	//wPtr = NULL;
	for(curr=headByName; curr; curr=curr->nextByName)
	{
		if(strcmp(curr->item.getName(), name) == 0)
		{
             wPtr = curr->item;  // causing error
			
		return wPtr;
		}
	}

Code:

[...]
	struct node
	{
		node(const winery& winery);		// constructor
		winery item;
		node * nextByName;
		node * nextByRating;
	};
[...]

"winery item" should be "winery * item"

I dont think so nadroj

So if find returns a real honest-to-goodness winery, then wPtr should most definitely not be a pointer, but a real honest-to-goodness winery, then.

what should it be then? either change "winery" to "winery*" in struct "node", or in function "find" assign "wPtr" the address of "curr->item".

edit: as tabstop mentions, the last option is to change the type of "wPtr". the point is you have a "winery*" and your trying to assign it the value of a "winery". you need to change one of the two types so that they are the same.

Thanks guys.. I couldnt change
winery item; It threw up alot of errors..

However, i did what you said and it works..
wPtr = &curr->item;

Thank you..