division by zero to any integer gives infinity answer instead of runtime error

This is a discussion on division by zero to any integer gives infinity answer instead of runtime error within the C++ Programming forums, part of the General Programming Boards category; Code: int main() { int z=0; int i=1/z; cout<<i; } It doesn't throw any error in Visual Studio 2008. .......What ...

  1. #1
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    division by zero to any integer gives infinity answer instead of runtime error

    Code:
    int main()
    {
    int z=0;
    int i=1/z;
    cout<<i;
    
    }
    It doesn't throw any error in Visual Studio 2008. .......What setting one has to change so that it will show runtime error in VS 2008.....

  2. #2
    Frequently Quite Prolix dwks's Avatar
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    Perhaps MSVC catches that particular error when you compile in debug mode. Or perhaps it's only an error when you do floating-point division by zero.
    dwk

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  3. #3
    DESTINY BEN10's Avatar
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    Quote Originally Posted by forumuser View Post
    Code:
    int main()
    {
    int z=0;
    int i=1/z;
    cout<<i;
    
    }
    It doesn't throw any error in Visual Studio 2008. .......What setting one has to change so that it will show runtime error in VS 2008.....
    In non-debug mode, it shows an error "MSVS has encountered an error. Sorry for inconvenience".
    In debug mode, it throws run time error, integer division by zero.
    HOPE YOU UNDERSTAND.......

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  4. #4
    Captain Crash brewbuck's Avatar
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    Quote Originally Posted by dwks View Post
    Perhaps MSVC catches that particular error when you compile in debug mode. Or perhaps it's only an error when you do floating-point division by zero.
    On Windows, FPU exceptions are normally disabled. A floating point divide-by-zero results in infinity, not an exception. If you want the exceptions you need to turn them on explicitly by calling _controlfp()

    For integer divide-by-zero an exception is always generated, because unlike IEEE floats there is no way to represent "infinity" and so there is no possible valid result of the division. An exception is the only choice.

    According to what the OP is reporting, I suspect the actual code was using floats instead of integers. There is no way for an integer division to result in "infinity." And I get very reliable exceptions for that integer divide-by-zero. I think the OP is confused.
    Code:
    //try
    //{
    	if (a) do { f( b); } while(1);
    	else   do { f(!b); } while(1);
    //}

  5. #5
    Malum in se abachler's Avatar
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    Damn you beat me to it brew
    Until you can build a working general purpose reprogrammable computer out of basic components from radio shack, you are not fit to call yourself a programmer in my presence. This is cwhizard, signing off.

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