Pointers

[effa]

hi all..
i'm a bit confused how the pointer works..

std::string n;

//is this right??

// i'll create an empty array of string with x elements in it
char * str = new char [x]

// if i want to fill in
strcpy(str,n.c_str)

let say n= "HELLO"
after i copy it does this mean *str= "HELLO" or str = "HELLO" ????
this also mean str[0] = 'H' ???


and another thing on double pointer

//create new space

char** word = new char* [num of str];

so what is the best way for me to copy *str into **word so the ouput for **word = "HELLO" ?? what i mean here is the word[0] = "HELLO" ...


thanks in advance

[abachler]

char str[] = "HELLO";

char* pStr = str;

printf("%s\n" , pStr);

output would be HELLO

[effa]

i understand that..but in order to create stack that is not possible.i cant use STL or vector for this stack assignment..so im trying to understand how pointers works then...

the way i think is:
the first pointer will be a list of char
the double pointer will be the list of word....


the first pointer should give me in 'H' 'E' 'L' 'L' 'O'
then in the second pointer will be "HELLO"... in the way the first pointer is a pointer to a list of stack...

so what is the best way for me to copy value in the first pointer to the double pointer..??
hm..does this makes sense to you? 0_0

[iMalc]

// i'll create an empty array of string with x elements in it

Incorrect. The code below that comment creates an "uninitialised" array.
"empty" would imply that it contains elements, which is not the case.

[iMalc]

Sorry, I mean contains no elements.

[effa]

hey iMalc.
do you mean i need to initialise the new array i created then i can use it later on?..but how?
most of the examples i've seen didnt initialise the new array.

another que: do you know a good way of getting the string from *str to **word?