Thread: using new to create a two-dimensional array

  1. #1
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    using new to create a two-dimensional array

    Can you use new to declare a two-dimensional array from a pointer? So far, I have this:

    int main()
    {
    float *a;
    a = new float[1][1];
    return 0;
    }


    I get the following error in the line with the new statement:
    '=' : cannot convert from 'float (*)[1]' to 'float *'

    Can you not declare a two-dimensional array from a pointer?

    Thanks

  2. #2
    Confused Magos's Avatar
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    reply

    I doubt it works the way you do it. You could make a "pointer to pointers" which is kind of 2D.
    Another solution is to make a 1D array which serves as a 2D:

    int* Pointer;
    Pointer=new int[x*y];


    Remember to deallocate the memory before you quit the program:

    delete[] Pointer;
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  3. #3
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    Re: reply

    Originally posted by Magos
    I doubt it works the way you do it. You could make a "pointer to pointers" which is kind of 2D.
    Another solution is to make a 1D array which serves as a 2D:

    int* Pointer;
    Pointer=new int[x*y];


    Remember to deallocate the memory before you quit the program:

    delete[] Pointer;
    Wouldn't that be interpreted as a 1-D array of size (x*y), i.e., x= 2, y = 3, an array Pointer = new int[6]; ?

  4. #4
    Confused Magos's Avatar
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    Yes

    Quote:
    Another solution is to make a 1D array which serves as a 2D

    Access it through Pointer[x+y*xsize]. Element x=2, y=4 in a 5x7 array is element 2+4*5=22 in this "simplified" array. You use a 1D array but handle it somewhat like a 2D array...
    MagosX.com

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  5. #5
    Skunkmeister Stoned_Coder's Avatar
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    read zens post here for an example on how to do this properly.
    Free the weed!! Class B to class C is not good enough!!
    And the FAQ is here :- http://faq.cprogramming.com/cgi-bin/smartfaq.cgi

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