how to store a largest numbers?

This is a discussion on how to store a largest numbers? within the C++ Programming forums, part of the General Programming Boards category; hi i have a problem. i want to store the largest numbers which is beyound the limit of all primitive ...

  1. #1
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    how to store a largest numbers?

    hi

    i have a problem.

    i want to store the largest numbers which is beyound the limit of all primitive data types.

    how can i store it?

  2. #2
    and the hat of wrongness Salem's Avatar
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    Use a library - The GNU MP Bignum Library
    If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
    If at first you don't succeed, try writing your phone number on the exam paper.
    I support http://www.ukip.org/ as the first necessary step to a free Europe.

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    i dont want to use the library.

    i want to do it not from library.

    i had listen that it can be possible through Xor operator or through string or may be from modulus operator.

    if any other way you know then kindly help me.
    thanks
    Last edited by maifs; 08-08-2009 at 03:27 AM.

  4. #4
    and the hat of wrongness Salem's Avatar
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    char thisIsAlargeNumber[] = "12334567879809644532341346578669";

    Now write your own class which wraps around this idea, and overloads +,-,*,/
    Job's as good as done.
    If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
    If at first you don't succeed, try writing your phone number on the exam paper.
    I support http://www.ukip.org/ as the first necessary step to a free Europe.

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    hi agian
    sory may be i didnt make you understand.

    actually its in the form like this.

    2 power of long limit.

    now have to save it .

  6. #6
    Registered User CrissyCrisCris's Avatar
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    Store it as

    Code:
    double dNumberSqrt;
    dNumberSqrt = sqrt(12334567879809644532341346578669);
    and when you need to display it

    Code:
    std::cout << dNumberSqrt * dNumberSqrt
    Is that what you mean? Your English is kind of choppy.

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