Hi guys I need to now that I can control the white spaces in the printf("%5d") defined by 5.
In my program I need to control it to implement or decrement. So instead of using %5 what can I use.
I need ideas, thanks for help!
Hi guys I need to now that I can control the white spaces in the printf("%5d") defined by 5.
In my program I need to control it to implement or decrement. So instead of using %5 what can I use.
I need ideas, thanks for help!
You can create the format string on the fly:
Code:char format[100]; sprintf(format, "%%%dd", 5); // or snprintf if available printf(format, some_int);
Eg.Originally Posted by man page
Code:printf( "%*d\n", 5, some_int );
If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
If at first you don't succeed, try writing your phone number on the exam paper.
actually I am trying to control
sprintf(*form, "%s", "%5d");
in this line %5d must be controlled by a variable!
and it is c++ but we're not using its GUI
What are you doing? You have already been given code to accomplish exactly this.in this line %5d must be controlled by a variable!
What GUI? If you are using C++, then you can also do this the C++ way.and it is c++ but we're not using its GUI
Code:std::cout << std::setw(5) << i << std::endl;
sorry it is
sprintf(form, "%s", "%5d");
not *form
If you're using C++, why not use cout and iomanip's setw?
but this must be controlled by a variable "%5d" part must be controlled
and also I am obligated to write in C but in c++ file
So you should read the man page on printf/sprintf/etc, and note how to use a variable to control the precision.
I ve already read but nothing founr so I am here!
Then you need to read better.
Originally Posted by man 3 printf