I need an explanation of part of the following function that is highlighted in red (possible typo). At first I thought the parenthesis to the right of c was a typo(this is from the book Accelerated C++) but the full code compiles and runs successfully. I don't understand why that parenthesis is there.
Code:bool not_url_char(char c) { // characters, in addition to alphanumerics, that can appear in a \s-1URL\s0 static const string url_ch = "~;/?:@=&$-_.+!*'(),"; // see whether `c' can appear in a \s-1URL\s0 and return the negative return !(isalnum(c) || find(url_ch.begin(), url_ch.end(), c) != url_ch.end()); }



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CornedBee
It was the last closing parentheses that made me force myself to look at it twice.