Quote Originally Posted by Steff View Post
That's the point. There is no total ordering on vectors in R^n. In other words, while [2,2]>[1,1], we do not have that [1,2] > [2,1] nor [2,1]>[1,2]. We do have a partial ordering, but sets in STL do not allow for this. As such, is there another way?
Of course there is a total ordering on vectors in R^n, it just may not be "natural". (The lexicographic order is one example.) Presumably, if you actually need a set of vectors, you have some comparison between them in mind.