unhandled execption

Hi, i got this program to book seats for a cinema show.if trying to book seats already booked,a exception is thrown.code is as follows.

Code:

try{
		if(ifFoundBookedSeats==true){
			if(invalidSeatList){
				cout<<"\n$$$$$$$$$$$$$$4";
			}
			cout<<"\nsize"<<invalidSeats.size();
			cout<<"\n &"<<invalidSeats[0];
			cout<<"\n &"<<invalidSeats[1];
			cout<<"\n &"<<invalidSeats[2];
           throw SeatsNotFreeException(invalidSeatList,invalidSeats.size());// error line
		}
	}
	catch(SeatsNotFreeException ex){
       	//try booking alternative seats
	//	if(ex.bookAlternativeSeats(showSeatList)==true){
    //        //replace invalid seat numbers with new seat numbers.
	//		adjustSeatList(seatList,numOfSeats,invalidSeats,ex.getNewValidSeats());
    //        isSeatsBooked=true;
	//	}
	}

when i run it,it gives me a error: unhandled excpetion at this line "throw SeatsNotFreeException(invalidSeatList,invalidSeats .size());"


when i run it in dev c++... it works fine..no error


run it in microsoft visual compiler.....dang..gives me error !

help !!!!

I don't think there is enough information. Have you perhaps disabled exceptions with one compiler and not with the other?

Some notes. Catch exceptions by reference. Generally I don't believe you should throw exceptions if you are going to handle it right there (part of normal program flow).

And tabs mixed with spaces = the indentation mess you can see in the code block.

I don't see why that would not work as is. It is sort of odd to see an exception thrown and then caught in the same try/catch block but it is valid. It's no different than calling a function in the try portion that throws on an error condition, however, as has been stated by anon I would recommend you do not throw exceptions if you are going to handle the exception in the same place. You could do the same thing without exceptions using return values.