Thread: switch statement that uses loop

  1. #1
    Registered User mike's Avatar
    Join Date
    Aug 2001
    Posts
    12

    switch statement that uses loop

    Hi
    I am trying to use a loop in this switch statement so i can have the user select another choice.
    here is my code. choice is an interger variable and the cases are funtion calls. they all work except i cant figure out the loop and where to put it. I thought it would go in the default section of the switch. hope you can help


    switch(choice)
    {
    case 1: smallest(first,second,third,fourth,fifth);
    break;
    case 2: largest(first,second,third,fourth,fifth);
    break;
    case 3: sum(first,second,third,fourth,fifth);
    break;
    case 4: average(first,second,third,fourth,fifth);
    break;
    case 5: printDisplay(first,second,third,fourth,fifth);
    break;
    default: cout<<"\aError! choice is (1) or (2) or (3) or (4) or (5) please try again\n";
    break;

    }

  2. #2
    Registered User
    Join Date
    Feb 2002
    Posts
    589
    Put the switch stament in the loop like so

    choice == TRUE;
    while(choiche)
    {
    switch(choice)
    {
    case 1: smallest(first,second,third,fourth,fifth);
    break;
    case 2: largest(first,second,third,fourth,fifth);
    break;
    case 3: sum(first,second,third,fourth,fifth);
    break;
    case 4: average(first,second,third,fourth,fifth);
    break;
    case 5: printDisplay(first,second,third,fourth,fifth);
    break;
    default: cout<<"\aError! choice is (1) or (2) or (3) or (4) or (5) please try again\n";


    ""Ask the user if they want to continue"" and set choice to FALSE if they don't""
    }
    }
    Last edited by Barjor; 02-22-2002 at 04:19 PM.

  3. #3
    ¡Amo fútbol!
    Join Date
    Dec 2001
    Posts
    2,138
    That will work but you used the same var twice when you should use 2 different variables for the loop and the switch where the one in the loop is set to true originally. Also, a do...while loop will work in this situation too.

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