Thread: Memory allocation

I'm just wondering if it's possible to allocate a matrix with the "new" command in any way like this:

matrix=new float [size][size];

I've tried most things, and can't find it anywhere on the net.



Leiken

Code:

int** matrix=new int*[size];

    for(int i=0;i<size;i++)
        matrix[i]=new int[size];

it's possible.

float ** maze;

maze = new float*[sizeA];
for(int i = 0; i < sizeA; i++)
{
maze[i] = new float[sizeB];
}

where sizeA and sizeB are integers. Also look up how to delete the dynamically memory so declared to prevent memory leaks in your program.

The answer to your question: No.
You have to use the code that Sorensen gave you.
Deleting this memory is as simple as

delete[] maze;

The rest should be automatically done when you call this.

>Deleting this memory is as simple as delete[] maze;

After looping through and deleting the indivdual pointer to floats using a similar method to the allocation.

Code:

 for (i=0;i<size;i++)
        delete [] maze[i];

    delete [] maze;

Thanks loads guys! I'm happy now..