Storing values into a dynamic array

I would like to know how to store a modified string into an array of type char. Below is my code:

Code:

typedef char* ArrayPtr;
  ArrayPtr array;
  array = new char[1000];
  istringstream break_apart(input);   
  while (break_apart >> word)
  {
    front = &word.at(0); 
    rear = &word.at(word.size() - 1); 
    while (front <= rear) 
    {
          swap (*front, *rear);
          front++;
          rear--;
    }
    cout << word << " ";
  }
  
  for (int i = 0; i < input.length(); i++)
  {
      //WHAT DO I PUT HERE?!?
  }

In the main part of the code there, I switched the positions of characters within the word to ultimately swap each word of 'input'. However, I need to store this modified string (originally 'input') into an array of type char. I know I have to use a for loop to copy it over, but what do I need to put inside the loop. I'm having trouble figuring this out... Thank you very much for all who help. I appreciate it!!!!

FYI - this post is simply a more specific version of my previous post. I solved the palindrome instance, so I'm simplifying so you all do not have to go through already solving info to receive the needed help.

Since you are using C Style strings, you should look into strcpy/strncpy.

i could, but I cannot cpy between type char and type string. in order for strcpy/strncpy to work i am almost positive that they have to be the same type.

Code:

strcpy(char_array, std_string.c_str());

thank you very much, I solved my problem. Thanks to all who contributed.

Please don't start a new thread on a topic already being discussed.