Quick Sizeof Question

This is a discussion on Quick Sizeof Question within the C++ Programming forums, part of the General Programming Boards category; At the top of my program I created a definition: Code: #define CRLF "\r\n" Which seems to work just fine ...

  1. #1
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    Quick Sizeof Question

    At the top of my program I created a definition:

    Code:
    #define CRLF "\r\n"
    Which seems to work just fine except for the fact that the sizeof(CRLF) returns 3 when I would expect the result to be a 2. Is this just a mistake on my part?

    Thanks,

    PetrolMan

  2. #2
    and the Hat of Guessing tabstop's Avatar
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    Code:
    \r = 1
    \n = 1
    \0 = 1
       ----
         3

  3. #3
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    \0 is a Null Character Right?

    Is there a way to prevent the \0 from being put in or is that even desirable in the first place?

    PetrolMan

  4. #4
    and the Hat of Guessing tabstop's Avatar
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    Every "string literal" ends with a null character. Whether you want that or not depends on how you use CRLF.

  5. #5
    Algorithm Dissector iMalc's Avatar
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    There's a multicharacter constant:
    Code:
    #define CRLF '\r\n'
    However that's implementation-defined behaviour, and wont be a direct replacement because then suddently it's not even an array.
    I don't think it makes sense to use sizeof on it. If you'd rather avoid using strlen on it, then just declare another constant with the value 2.
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