Hi, if I have a basic function, lets say sampleStr which contains some string. I have another, integer, function and would like to add the result of that function, in integer format to the end of the string, then how can I do it.
I have tried what I think i should do, but that only returns the relative character (ie I want 65 put in, but 'A' is put in instead.
Thanks in advance,
mintsmike
Look up the stringstream (ostringstream in particular), within the standard <sstream> header.
Alternatively, if you want to use the "C way", look up sprintf() in <stdio.h> or <cstdio>.
Yes, you need something that translates a number into a string of characters that represent that number. Stringstreams will work.
EDIT: of course, this program prints number that's random until you look at it. Then it won't seem so random when the you it again.Code:#include <cstdlib> //rand() #include <string> #include <sstream> #include <iostream> int main() { std::string initial("This number was generated randomly: "); std::ostringstream oss; oss << std::rand(); initial += oss.str(); std::cout << initial << std::endl; }
Last edited by CodeMonkey; 03-27-2009 at 04:12 PM.
"If you tell the truth, you don't have to remember anything"
-Mark Twain
It's too bad that operator << always returns an ostream&. If somehow it remembered what type was involved we could:
Maybe in another lifetime.Code:cout << (ostringstream() << number << date << string << 'a').str() << endl;
"If you tell the truth, you don't have to remember anything"
-Mark Twain
What?cout << (ostringstream() << number << date << string << 'a').str() << endl;
Not much different from:
Code:std::ostringstream ostrm; ostrm << number << date << string << 'a'; std::cout << ostrm.str().c_str() << std::endl;
Two lines different.
"If you tell the truth, you don't have to remember anything"
-Mark Twain
In labouring to be concise, your code eventually becomes obscure or unmaintainable.Originally Posted by CodeMonkey
O_oCode:cout << (ostringstream() << number << date << string << 'a').str() << endl;
SomaCode:cout << number << date << string << 'a' << endl;
Well there's the coup de grāce.
"If you tell the truth, you don't have to remember anything"
-Mark Twain
But you might want something that turns an integer into a string with only one line, ala boost::lexical_cast. That's not very obscure.
