Thread: Calling a function within a function

Hi,

Im trying to call a function within a function but the 2nd function isnt returning anything.
The code compiles fine.

Code:

void playerMove(char playerInput,int playerRow,int playerCol,int theGrid[][10])
{
	getPlayerPos(playerRow,playerCol,theGrid);
}

its the function getPlayerPos that isnt returning any values.but if I call the getPlayerPos outside of playerMove it works.

Code:

int getPlayerPos(int& playerRow,int &playerCol,int theGrid[][10])
{
	for(int row=0;row<10;row++){
		for(int col=0;col<10;col++){
			if(theGrid[row][col]==1){
				playerRow=row;
				playerCol=col;
				return playerRow,playerCol;
			}
		}
	}
}

Any ideas?

Code:

void func1 (int &a) {
  func2 (a);
}

void func2 (int &a) {
  a = 3;
}

pass the arguments to 'playerMove' as references aswell if you want to be able to change their values.

Also:

Code:

return playerRow,playerCol; /* this is the same as 'return playerCol;' */

Ok I understand you both.I see where I was goin wrong.

I know that there is always going to be a 1 value in the array(well there should be!)
I take it that its a bad practice to to leave that if statement open ended should I always qaulify it with an else statement?

thanks for the speedy reply's!

Thanks.