Thread: Error in return variable.

Hey all. I am new to C and C++

I am doing a test program and it does not return the variable called input in the input2 function. any help would be great.

Code:

#include <iostream>
using namespace std;
int input2(int input);

int main (int argc, char * const argv[]) {
    // insert code here...
//int input=0;
	int input;
	//input=0;
	input2(input);
	
    
	
	cout<<input;
	switch(input)
	{
		case 1:
			printf("New Game");
			break;
		case 2:
			printf("Load Game");
			break;
		case 3:
			printf("high scores");
			break;
		case 4:
			printf("Quiting!");
			break;
		default:
			printf("Invalid Choice!");
			break;
			
	}
	getchar();

    return 0;
}

int input2(int input){
	//int input;
	//int test;
	
	std::cout << "Hello, World!\n";

	printf("\n\n1. Play Game\n");
	printf("2. Load\n");
	printf("3. High Scores\n");
	printf("4. Quit\n\n");
	printf("Selection:  ");
	cin>>input;
	cin.ignore();
	
	cout<<"\n"<<input<<"\n";
	//test==input;
	return input;
	
}

You have to store the return variable somewhere, for example:

Code:

int input = 9;
int root = 0;

root = get_square_root(input);

// now root is 3.

Your current code uses an input parameter, but that doesn't change the variable in main. (There is a slightly more advanced technique called pass-by-reference that would do that, but that's not what you want here.) You don't need a parameter, you just need to use the return value.

Thanks.. That worked wonderfully.

It was so obvious. I don't know how I missed that.