Thread: returning a reference to string

  1. #1
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    returning a reference to string

    Hi,

    How do I properly put this to code? I am trying to return a string (name) from a function using reference.

    Code:
    std::string& name()
    {
       cout << "Enter your name: " << endl;
       getline(cin, name);
    }
    I hope you get the idea. Thanks!

  2. #2
    C++ Witch laserlight's Avatar
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    You need to pass in the string by reference, but you probably should either rename the function or use a different name for the string reference parameter. Of course, once you pass in the string by reference, there is not much point in returning it at all.
    Quote Originally Posted by Bjarne Stroustrup (2000-10-14)
    I get maybe two dozen requests for help with some sort of programming or design problem every day. Most have more sense than to send me hundreds of lines of code. If they do, I ask them to find the smallest example that exhibits the problem and send me that. Mostly, they then find the error themselves. "Finding the smallest program that demonstrates the error" is a powerful debugging tool.
    Look up a C++ Reference and learn How To Ask Questions The Smart Way

  3. #3
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    I think there are some cases that benefit from returning a reference. For example, I have a function to convert something to a string, and use the converted string in a string expression. I can pass in a string reference, store the converted string in it, and return a reference to it. This way, I can avoid a string copy operation. Here is some abstract code to explain what I mean:
    Code:
    string & int2str(int i, string & str){
      // convert i into str
      return str;
    }
    
    int main(){
    
      ...
      string tmp;
      string a = "abc" + int2str(20, tmp);
      ...
    }

    Quote Originally Posted by laserlight View Post
    You need to pass in the string by reference, but you probably should either rename the function or use a different name for the string reference parameter. Of course, once you pass in the string by reference, there is not much point in returning it at all.

  4. #4
    C++ Witch laserlight's Avatar
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    Quote Originally Posted by plutino
    I think there are some cases that benefit from returning a reference.
    Yes, but I do not think that this is one of them.

    Quote Originally Posted by plutino
    This way, I can avoid a string copy operation.
    Depending on your point of view, you either cannot avoid the copy (since you are initialising a new string with a temporary) or can avoid the copy either way, e.g.,
    Code:
    string tmp;
    int2str(20, tmp);
    string a = "abc" + tmp;
    Quote Originally Posted by Bjarne Stroustrup (2000-10-14)
    I get maybe two dozen requests for help with some sort of programming or design problem every day. Most have more sense than to send me hundreds of lines of code. If they do, I ask them to find the smallest example that exhibits the problem and send me that. Mostly, they then find the error themselves. "Finding the smallest program that demonstrates the error" is a powerful debugging tool.
    Look up a C++ Reference and learn How To Ask Questions The Smart Way

  5. #5
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    The compiler can also optimize away functions returning copies of variables, if they are not too complicated.
    But you cannot return a reference to a local variable!
    Quote Originally Posted by Adak View Post
    io.h certainly IS included in some modern compilers. It is no longer part of the standard for C, but it is nevertheless, included in the very latest Pelles C versions.
    Quote Originally Posted by Salem View Post
    You mean it's included as a crutch to help ancient programmers limp along without them having to relearn too much.

    Outside of your DOS world, your header file is meaningless.

  6. #6
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    You are right. I guess the only benefit (depending on your point of view) is to make the code more compact.

    Quote Originally Posted by laserlight View Post
    Yes, but I do not think that this is one of them.


    Depending on your point of view, you either cannot avoid the copy (since you are initialising a new string with a temporary) or can avoid the copy either way, e.g.,
    Code:
    string tmp;
    int2str(20, tmp);
    string a = "abc" + tmp;

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