for loop, multiple checks

Is there a way to shorten this?

Code:

for(foo == bar || foo == pub)
{
      // Incert drunken code here
}

More specifically, is there a way to as such:

Code:

for(foo == bar||pub){}

Any help would be appreciated

-Thank You

Nope.

Friends don't let friends code drunk.

Code:

for(foo == bar)
{
       for(foo == pub)
       {
        }
break
}

errm oh wait thats not shorter

You might be able to use bit checks:

Code:

enum { bar = 1 << 0, pub = 1 << 1 };

while (foo & (bar | pub))
...

It can be done, it can be approximated, but how much work are you willing to put into making this expression style work?

I only ask because the code below illustrates about 1/200 of what you'd actually need to cleanly pull off this semantic modification.

Soma

Code:

template
<
   typename type_F
>
struct lhs_type
{
   lhs_type
   (
      const type_F & value_f
   ):
      value_m(value_f)
   {
   }
   const type_F & value_m;
};

template
<
   typename type_F
>
lhs_type<type_F> lhs
(
   const type_F & lhs_f
)
{
   return(lhs_type<type_F>(lhs_f));
}

template
<
   typename type_F
>
struct rhs_type
{
   rhs_type
   (
      const type_F & value_f
   ):
      value_m(value_f)
   {
   }
   const type_F & value_m;
};

template
<
   typename type_F
>
rhs_type<type_F> rhs
(
   const type_F & rhs_f
)
{
   return(rhs_type<type_F>(rhs_f));
}

template
<
   typename lhs_F,
   typename rhs_F
>
struct lor_type
{
   lor_type
   (
      const lhs_F & lhs_f,
      const rhs_F & rhs_f
   ):
      lhs_m(lhs_f),
      rhs_m(rhs_f)
   {
   }
   const lhs_F & lhs_m;
   const rhs_F & rhs_m;
};

template
<
   typename lhs_F,
   typename rhs_F
>
lor_type<lhs_F, rhs_F> operator ||
(
   const lhs_type<lhs_F> & lhs_f,
   const rhs_type<rhs_F> & rhs_f
)
{
   return(lor_type<lhs_F, rhs_F>(lhs_f.value_m, rhs_f.value_m));
}

template
<
   typename lhs_F,
   typename rhs_lhs_F,
   typename rhs_rhs_F
>
bool operator ==
(
   const lhs_F & lhs_f,
   const lor_type<rhs_lhs_F, rhs_rhs_F> & rhs_f
)
{
   return((lhs_f == rhs_f.lhs_m) || (lhs_f == rhs_f.rhs_m));
}

struct operator_placeholder_type{} operator_placeholder;

template
<
   typename lhs_F
>
lhs_type<lhs_F> operator ||
(
   const lhs_F & lhs_f,
   const operator_placeholder_type & rhs_f
)
{
   return(lhs_type<lhs_F>(lhs_f));
}

template
<
   typename lhs_F,
   typename rhs_F
>
lor_type<lhs_F, rhs_F> operator ||
(
   const lhs_type<lhs_F> & lhs_f,
   const rhs_F & rhs_f
)
{
   return(lor_type<lhs_F, rhs_F>(lhs_f.value_m, rhs_f));
}

#include <iostream>

#define my_log_or || operator_placeholder ||

int main()
{
   if(3 == (lhs(3)||rhs(5)))
   {
      std::cout << '(' << 3 << ':' << 3 << ':' << 5 << ')' << '\n';
   }
   if(4 == (lhs(3)||rhs(5)))
   {
      std::cout << '(' << 4 << ':' << 3 << ':' << 5 << ')' << '\n';
   }
   if(5 == (lhs(3)||rhs(5)))
   {
      std::cout << '(' << 5 << ':' << 3 << ':' << 5 << ')' << '\n';
   }
   if(6 == (6 my_log_or 8))
   {
      std::cout << '(' << 6 << ':' << 6 << ':' << 8 << ')' << '\n';
   }
   if(7 == (6 my_log_or 8))
   {
      std::cout << '(' << 7 << ':' << 6 << ':' << 8 << ')' << '\n';
   }
   if(8 == (6 my_log_or 8))
   {
      std::cout << '(' << 8 << ':' << 6 << ':' << 8 << ')' << '\n';
   }
   return(0);
}

Originally Posted by phantomotap

It can be done, it can be approximated, but how much work are you willing to put into making this expression style work?

That's reminiscent of Boost::MPL. In fact, if you had access to Boost::MPL, you could slap together something like what the OP is asking in just a few minutes.

The question is why you'd want to.

^_^

Well, if you had access to 'Boost::Spirit::Phoenix'... you'd mostly be done.

Soma