Originally Posted by

**brewbuck** If you understand decimal then you understand hexadecimal.

In decimal we have the one's place, the ten's place, the hundred's place, etc.

In hex we have the one's place, the sixteen's place, the 256's place, etc.

In decimal, each "place" is bigger by a factor of ten. In hex, by a factor of sixteen.

The problem is we only have ten Arabic numerals, but we have to represent sixteen digits, so we use the six letters A, B, C, D, E, F for the excess.

Given this, does Laserlight's calculation make any more sense?

7B -- in the one's place there is a 'B', which is eleven. In the sixteen's place is a 7. So you have seven sixteens, which is 112. Plus another eleven, which is 123.