Menu in C++

[JOCAAN]

Hi I'm making a menu in C++ for a sudoku puzzle solver program I've already wrote using switch setence.
I've wrote that code:

#include<stdio.h>
#include<stdlib.h>
#include<conio.h>
#include<iostream.h>

int opcio1();
int opcio2();
int opcio3();


int main(){

    char sel;

 

    cout <<"Sudoku\n\n\n"<<endl;
    cout <<"1. How to\n\n"<<endl;
    cout <<"2. Sudoku generator\n\n"<<endl;
    cout <<"3. Play!\n\n"<<endl;
    cout <<"4. Exit\n\n"<<endl;
   
    cout <<"Select an option, please..."<<endl;

 

    do{

        sel=getch();

    }while((sel<'1' || sel>'4')&&sel!=27); //esc=ASCII 27 

 

    switch(sel){

        case '1':

            opcio1();

            break;

 

        case '2':

            opcio2();

            break;

 

        case '3':

            opcio3();

            break;

 


        case 27:

            return;

                
    }

}

 

 

int opcio1(){

    cout <<"How to\n\n"<<endl;

}

 

int opcio2(){

   cout <<"Sudoku generator\n\n"<<endl; 

}

 

int opcio3(){

    cout <<"Play\n\n"<<endl;

}

This code works.
My question is how to do a return to the menu option inside every option in the menu?
I've tried to use goto but it only works for inside the same function.
Thank you

[Codeslinger]

Move the select statement inside the do while loop

do
{
    sel=getch();
    switch(sel)
    {
        case '1': opcio1() ; break ;
        case '2': opcio2(); break ;
        case '3': opcio3(); break;
        default: break ;
     }
}while(sel != 27) ;

Hope this helps

[nga_tom]

ahh Grasshopper, you have not yet learned of loops and return values. To make your menu always reappear (by magic of course) place it inside of a for(; (this is supposed to be another semicolon and a right paren not a smiley face) loop, include your menu and the do while statement - add an appropriate break after the while line.
Next visit each of your opcio functions and either give them an int return value or declare them as void, someone on this board has a signature that refers to compiler warnings and errors - pay attention to them, they are not there for decoration.

tom

[mikeman118]

#include<stdio.h>
#include<stdlib.h>
#include<conio.h>
#include<iostream.h>

What's with all of these headers? At least change it to <iostream>. I can't believe this compiles, because you don't put std::cout or std::endl, and you don't use "namespace std" or anything like that.

>>sel=getch();
I think it's Elysia's sig that says not to use this (I don't know why myself). But why not just use "std::cin >> sel;"?

I don't see why you don't just use ints for this, although I guess you're wanting to see if they pressed escape.

case 27:

return;

If you have "int main()" (like you should), you can't just put "return". It must be "return 0" or something like that.

Anyway, now that I'm complaining about your code , to your original question. Since your functions (opcio1, opcio2, etc.) are not void, they're supposed to return a value.
Since they return a value you could do something like this:

int opcio1(){

    cout <<"How to\n\n"<<endl;
    return 0; //Or whatever value you want to return at the end
}

        case '1':

            int ret = opcio1(); //If you want to know the return value, otherwise you don't need this
            //Now the function has returned, and you can keep doing stuff under "case '1'" until you want to break
            
            break;

Hope this helps.

Ahhh, too slow.

[bobknows]

just make the menu a function, then set a value for each choice, cin the choice, implement the menu option based on the choice with a switch, then return

[phantomotap]

O_o

This marks the forth useless old bump I'm aware of; are you doing this on purpose?

Soma

[nimitzhunter]

probably he just clicked on the tag with anything regarding sudoku without looking at the date.