Error that isn't an error

Hi, I'm new to programming and I'm trying out some basic codes. I'm using Gedit as a text editor and g++ to compile in my CLI. I am learning basic i/o right now so I wrote this little code to try it out.

Code:

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#include <iostream>

using namespace std;

int main ()
{
        int age;
        int zip;

        age = 20;
        zip = 50021;

        cout << "I am " << age << " years old." endl;
        cout << "My zipcode is " << zip << ".";

        return 0;
}

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I get this error message when I try to compile it:

Code:

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[metatron@Babylon Desktop]$ g++ -o ioexp ioexp.cpp
ioexp.cpp: In function ‘int main()’:
ioexp.cpp:15: error: expected `;' before ‘endl’

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I gather that it's telling me in line 15 I need a ";" before the "endl" command but firstly, I shouldn't need that right? It comes AFTER the "endl." And second, when I did try that I got another error anyway, which I expected.
Any ideas?

first:

Quote:

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Error that isn't an error

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compilers are incredibly "intelligent" pieces of software--they do not lie.

the line in question does have an error in it:

Code:

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cout << "I am " << age << " years old." endl;

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you are trying to concatenate " years old." and 'endl'. in order to concatenate, you have to use "<<", as you did with the other strings.

Thanks, you know, when I came back to it and looked again I figured that too. The problem was that I was using a bit of code in a tutorial as a reference and it was not a complete line of code. Thanks for getting back! I look forward to utilizing this forum as I learn.

As a side note, this isn't C. You don't have to declare all your variables at the top of your function.
This:

Code:

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int age;
int zip;

age = 20;
zip = 50021;

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could have just as easily (and probably more clearly) been written as:

Code:

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int age = 20;
int zip = 50021;

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Thanks, I was a little mixed up about that so I just wrote it all out to make myself feel better :)