a really really simple problem...

This is a discussion on a really really simple problem... within the C++ Programming forums, part of the General Programming Boards category; i really need a big help.. i just started learning C++.. the problem is this.. i need to write a ...

  1. #1
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    Question a really really simple problem...

    i really need a big help..
    i just started learning C++..
    the problem is this..

    i need to write a code in which
    the user inputs two numbers (3 and 5, for example..)
    and it goes as follows:
    243

    which is..
    3 x 3 x 3 x 3 x 3...
    notice how 3(the first number) was multiplied 5(second number) times.
    this needs to be done using two functions..
    and it needs to include #include<stdio.h>

    int main(void) and
    int multiply(int a)

    can somebody please help me out with this?
    Last edited by geshupenst; 11-12-2008 at 10:58 AM.

  2. #2
    and the hat of wrongness Salem's Avatar
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    So have you done either of these?
    - reading user input
    - for loops

    If you have, you're not completely stuck.

    Also, stdio.h is C, not C++.
    So you need to clarify which you're actually using.
    If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
    If at first you don't succeed, try writing your phone number on the exam paper.
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  3. #3
    Its hard... But im here swgh's Avatar
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    Your actually talking about the "base - exponent" feature of integers.
    As a small hint, try to think how you would calculate that. You know it will use mutliplication, but the trick is deciding what to multiply against what, and how many times.
    I'm just trying to be a better person - My Name Is Earl

  4. #4
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    wow thanks a lot
    that helped alot
    took me some time, but got it done ha!

  5. #5
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    Code:
    #include <stdio.h>
    #include <math.h>
    
    int power(int, int);
    
    int main()
    {
    	int x, y, z;
    
    
    	printf("Please enter two numbers : \n");
    	scanf("&#37;d",&x);
    	scanf("%d",&y);
    	z = power(x,y);
    	
    	printf("%d power %d : %d\n", x, y, z);
    }
    
    int power(int a, int b)
    {
    	 if (b==1)
    	 return a;
    	
    	 else
    	 return (a * power(a, b-1));
    }
    oh... C.. right. hehe
    this is how i got it done..
    how is it?
    Last edited by geshupenst; 11-12-2008 at 04:25 PM. Reason: Not C++.. sorry 'bout that

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