Such a simple problem

This is a discussion on Such a simple problem within the C++ Programming forums, part of the General Programming Boards category; Title says its all! Cannot figure out why when I print "totalFee" im getting 0.00 as output although I am ...

  1. #1
    Its hard... But im here swgh's Avatar
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    Such a simple problem

    Title says its all!

    Cannot figure out why when I print "totalFee" im getting 0.00 as output although I am passing it by reference to the function. At no point can I see why the variable is not adding the "charge" value. I am not getting errors or warnings. It looks like quite a small mistake im making.

    Can anyone see what I am doing wrong?

    Code:
    #include <iostream>
    #include <iomanip>
    
    // function prototype
    double calculateCharge ( double, double& );
    
    // main function - driver //////////////////////////////////////////////////////
    //
    int main ( void )
    {
    	std::cout << std::setprecision ( 2 ) << std::fixed;
    
    	double time1 = 0,
    	           time2 = 0,
    	           time3 = 0,
    	           totalTime = 0,
    	           totalFee = 0;
    
    	std::cout << "Enter stay times for three cars: ";
    	std::cin >> time1 >> time2 >> time3;
    
    	totalTime = time1 + time2 + time3;
    
    	std::cout << "\nCAR\tSTAY\tFEE\n\n"
    			  << " 1\t" << time1 << "\t" << calculateCharge ( time1, totalFee )
    			  << "\n 2\t" << time2 << "\t" << calculateCharge ( time2, totalFee )
    			  << "\n 3\t" << time3 << "\t" << calculateCharge ( time3, totalFee )
    			  << "\n\nTotal Time: " << totalTime
    			  << "\nTotal Fee: " << totalFee << std::endl;
    
        std::cin.get(); // freeze console output window
    	std::cin.ignore();
    
        return 0; // return value from int main
    }
    
    // function to calculate the charge
    // for each car stayed
    double calculateCharge ( double x, double &rFee )
    {
    	double charge = 0;
    
    	if ( x <= 3.00 )
    	{
    		charge = 2.00;
    		rFee += charge;
    	}
    
    	if ( x > 3.00 )
    	{
    		double timeOverStandard = 0,
    			   additionalCharge = 0;
    
    		timeOverStandard = x - 3.00;
    		additionalCharge = timeOverStandard * 0.5;
    
    		charge = 2.00 + additionalCharge;
    		rFee += charge;
    	}
    
    	if ( x == 24.00 )
    	{
    		charge = 10.00;
    		rFee += charge;
    	}
    
    	return charge;
    }
    I'm just trying to be a better person - My Name Is Earl

  2. #2
    Registered User hk_mp5kpdw's Avatar
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    Elementary my dear Watson. One possible fix... change:
    Code:
    	std::cout << "\nCAR\tSTAY\tFEE\n\n"
    			  << " 1\t" << time1 << "\t" << calculateCharge ( time1, totalFee )
    			  << "\n 2\t" << time2 << "\t" << calculateCharge ( time2, totalFee )
    			  << "\n 3\t" << time3 << "\t" << calculateCharge ( time3, totalFee )
    			  << "\n\nTotal Time: " << totalTime
    			  << "\nTotal Fee: " << totalFee << std::endl;
    To:
    Code:
    std::cout << "\nCAR\tSTAY\tFEE\n\n"
             << " 1\t" << time1 << "\t" << calculateCharge ( time1, totalFee )
             << "\n 2\t" << time2 << "\t" << calculateCharge ( time2, totalFee )
             << "\n 3\t" << time3 << "\t" << calculateCharge ( time3, totalFee )
             << "\n\nTotal Time: " << totalTime;
    std::cout << "\nTotal Fee: " << totalFee << std::endl;
    I'll let you think about the "why".
    "Owners of dogs will have noticed that, if you provide them with food and water and shelter and affection, they will think you are god. Whereas owners of cats are compelled to realize that, if you provide them with food and water and shelter and affection, they draw the conclusion that they are gods."
    -Christopher Hitchens

  3. #3
    Jack of many languages Dino's Avatar
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    Good one.
    Mac and Windows cross platform programmer. Ruby lover.

    Quote of the Day
    12/20: Mario F.:I never was, am not, and never will be, one to shut up in the face of something I think is fundamentally wrong.

    Amen brother!

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