C++ Question

This is a discussion on C++ Question within the C++ Programming forums, part of the General Programming Boards category; Hello, i got a problem with this question with my C++ lab reports, i was wondering if anyone could tell ...

  1. #1
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    C++ Question

    Hello, i got a problem with this question with my C++ lab reports, i was wondering if anyone could tell me why it isn't working properly, the code is:

    Lab Exercise 3a

    What output will be produced by the following code when embedded in a complete program?
    Consider initial values for first_choice of 0, 1 and -1.

    Code:
    int x = first_choice++;
    switch (first_choice + x)
    {
      case 1: cout << "Waitrose\n" break;
    
      case 2: cout << "Sainsburys\n" break;
    
      case 3: cout << "Tesco\n" break;
    
      case 4: cout << "Asda\n" break;
    
      default: cout << "No shopping today!\n";
    }
    So i made this to figure out the answer:
    Code:
    #include "stdafx.h"
    #include <string>
    #include <iostream>
    
    using namespace std;
    
    int main()
    
    int x = first_choice++;
    switch (first_choice + x)
    {
      case 1: cout << "Waitrose\n" break;
    
      case 2: cout << "Sainsburys\n" break;
    
      case 3: cout << "Tesco\n" break;
    
      case 4: cout << "Asda\n" break;
    
      default: cout << "No shopping today!\n";
    }
    
    return 0;
    
    }
    Anyone know why, i get illegal case and illegal break errors.

    Thanks

  2. #2
    Registered User whiteflags's Avatar
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    I think the intent of your lab question was that you be the computer and reason the output for yourself. The question mentions that the code provided is not a complete program, so you'll have to revise the code accordingly if you're too lazy to think it through.

  3. #3
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    every statement must have a semicolon after it, so "cout << "Waitrose\n" break;" is considered one statement (which doesnt make sense). after your cout statement (before break) you need to tell the compiler that the statement is done, by inserting a semicolon.

    it is actually easier to follow the example without doing any coding. there is no trick involved. for example, if first_choice is 0, x will be 0, so their sum is 0, and there is no case for this so it will execute the default case.

  4. #4
    Lode Runner
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    Quote Originally Posted by nadroj View Post
    for example, if first_choice is 0, x will be 0, so their sum is 0, and there is no case for this so it will execute the default case.
    Because of the first_choice++, first_choice will have been incremented when it gets to the switch statement, so:

    x + first_choice = 0 + 1 = 1

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