Suppose I have a data member for a struct which is a pointer to char
Code:struct Sample { char* sPtr; // more code......... }; int main() { // Now how do you dynamically allocate a string for char* ?? // My try // Sample a; // a.sPtr = new char "Hello World!"; // but this doesnt works whats the correct syntax ? return 0; }
You need to allocate memory - by specifying the number of chars you need / want.
char* p = new char[n];
If you need enough chars to store "Hello World!", then you can use sizeof:
char* p = new char[sizeof("Hello World!")];
After that, you actually need to copy the string into the storage with strcpy.
But a better way in C++ is just to make a std::string and assign "Hello World!" directly.
No messing with new/delete and it's simple.
Don't forget that all you allocate with new must be freed with delete.
Originally Posted by Adak
ok thanks i know std::string
but i doing book exercises thats why Im restricted to use char pointers only
thanks any way
Alright, that's fine. Just so that you are aware.
Good luck.
Code:#include <iostream> using std::cout; using std::endl; struct Sample { int one; int two; char* sPtr; }; int main() { Sample a; Sample b; a.one = 5; a.two = 10; a.sPtr = new char[sizeof("Hello World!")]; a.sPtr = "Hello World!"; b = a; cout << a.one << " " << a.two << " " << a.sPtr; cout << endl << b.one << " " << b.two << " " << b.sPtr << endl; // Changing the content of a.sPtr a.sPtr[0] = 'h'; // Error why??????? cout << a.one << " " << a.two << " " << a.sPtr; cout << endl << b.one << " " << b.two << " " << b.sPtr << endl; return EXIT_SUCCESS; }
I have allocated the char successfully but now im getting errors when modifying it
Because after you allocate the memory, you change it to point to the constant memory area that holds "Hello, World!", which you can not write to. You need to make a copy of the string into your allocated memory.
--
Mats
Compilers can produce warnings - make the compiler programmers happy: Use them!
Please don't PM me for help - and no, I don't do help over instant messengers.
http://cpwiki.sourceforge.net/Common...kes_and_errors
I told you to use strcpy.
You are assigning a string literals, which means:
1) It's const char*, not char*, hence NOT supposed to be modifiable.
2) All the memory you allocated before is lost.
And for the sake of it:
3) FREE your memory with delete before you exit!
This is bad. You allocated enough memory on the first line and then you leaked it on the second line by pointing to a "string literal" instead. Look into strcpy() for copying the contents of the literal into the allocated.
"You are stupid! You are stupid! Oh, and don't forget, you are STUPID!" - Dexter
Thanks Elysia, matsp and FillYourBrain. You all are programming masters! How the hell do you guys know every thing?
you're a genius thanks.
no idea how many thanks im giving you right now... THANKS THANKS THANKS..
thx for the help Elysia, matsp and FillYourBrain, appreciate it alot.
