Easy problem with while!

This is a discussion on Easy problem with while! within the C++ Programming forums, part of the General Programming Boards category; Hi, I have some problems with syntax when i have this inside my code: Code: string val; while(val != "1" ...

  1. #1
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    Easy problem with while!

    Hi,

    I have some problems with syntax when i have this inside my code:

    Code:
    	string val;
    	
    	while(val != "1" && != "2"){
    ....
    
    }

  2. #2
    and the Hat of Guessing tabstop's Avatar
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    Well, so what in particular do you not want to equal "2"?

  3. #3
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    i get these syntax errors

    C:\Program Files\Microsoft Visual Studio\MyProjects\44\44.cpp(16) : error C2059: syntax error : '!='

    C:\Program Files\Microsoft Visual Studio\MyProjects\44\44.cpp(16) : error C2143: syntax error : missing ';' before '{'

  4. #4
    and the Hat of Guessing tabstop's Avatar
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    We know.

    You need to say what, in particular, you want to not equal 2. Right now you are saying that you don't want __________ to equal 2, but that doesn't help; you need to fill in the blank.

  5. #5
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    Here is the code so far for an easy phone book. While the string variable is not equal to either 1 or 2 i would like the program to loop the first phase of the options 1 or 2.

    Code:
    #include <iostream>
    #include <fstream>
    #include <string>
    using namespace std;
    
    struct telefon{
    
    	string namn;
    	string nummer;
    };
    
    int main(){
    	
    	string val;
    	
    	while(val != "1" && != "2"){
    	
    		cout << "Enter 1 or 2 for either option..." << endl << endl;
    
    		cout << "1." << '\t' << "login to Adams phonebook" << endl;
    		cout << "2." << '\t' << "exit program" << endl << endl;
    		cout << "Enter choice: ";
    		getline(cin, val);
    
    		if (val == "1"){
    		
    			string pass;
    	
    			cout << "Welcome to Adams phonebook, please insert password to continue..." << endl << endl;
    			cout << "password: ";
    			getline(cin, pass);
    	
    			if(pass == "bajskorv"){}
    			
    			else{
    			cout << endl << endl << "worng password please try again...";
    			}
    
    		}
    	}
    
    	if (val == "2"){
    	exit(1);
    	}
    
    
    	
    	
    	
    return 0;
    }

  6. #6
    and the Hat of Guessing tabstop's Avatar
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    So the line
    Code:
    while(val != "1" && != "2")
    means "while val doesn't equal 1 and ____________ doesn't equal 2". You need to fill in the blank with the variable you want to not equal 2.

  7. #7
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    thank you!!!! Silly me by doing such a miss !!!

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