Digital calculator :D

This is a discussion on Digital calculator :D within the C++ Programming forums, part of the General Programming Boards category; Nothing. Just posting this for fun. it takes around 30 seconds to make. I accomplished alot of things. I'm learning ...

  1. #1
    deletedforumuser
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    Digital calculator :D

    Nothing. Just posting this for fun. it takes around 30 seconds to make.

    I accomplished alot of things. I'm learning Direct3d right now.

    Well, about 5 months ago. I was trying to make a small console digital calculator. I didn't even finished it and it was around 1000+ line of codes.

    Now, today, i just said, why not try the digital calculator again with my C++ skills.

    Haha, i just realized how easy it was.

    Here's the code.

    Code:
    
    #include<iostream>
    #include<string>
    using namespace std;
    int main()
    {
    float value1;
    string variable = "";
    float value2;
    while(1)
    {
    cout<<">>";
    cin >> value1;
    cin >> variable;
    cin >> value2;
    cin.get();
    if(variable == "+")
    {
    cout <<value1 + value2;
    }
    else if(variable == "-")
    {
    cout <<value1 - value2;
    }
    else if(variable == "/")
    {
    cout <<value1 / value2;
    }
    else if(variable == "*")
    {
    cout <<value1 * value2;
    }
    cin.get();
    system("cls");
    }
    cin.get();
    return 0;
    }
    
    Oh well, back to Directx. Cya.

    By the way, if your wondering how to use it.
    Example:


    5 * 5
    5 + 5

    Dont forget the spaces.

    5(space) * (space) 5
    Last edited by kevinawad; 10-04-2008 at 10:34 PM.

  2. #2
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    Just a comment - I think the "variable" should be more appropriately called the "operator" .

  3. #3
    C++まいる!Cをこわせ! Elysia's Avatar
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    You somehow also messed up indentation of the code you posted (but I do assume you properly indented the code when you wrote it).
    Simple, but effective. You can't ask for more, can you?
    Quote Originally Posted by Adak View Post
    io.h certainly IS included in some modern compilers. It is no longer part of the standard for C, but it is nevertheless, included in the very latest Pelles C versions.
    Quote Originally Posted by Salem View Post
    You mean it's included as a crutch to help ancient programmers limp along without them having to relearn too much.

    Outside of your DOS world, your header file is meaningless.

  4. #4
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    I think it would take no more lines in straight C.

  5. #5
    C++まいる!Cをこわせ! Elysia's Avatar
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    It probably would not. It's a too simple application.
    Quote Originally Posted by Adak View Post
    io.h certainly IS included in some modern compilers. It is no longer part of the standard for C, but it is nevertheless, included in the very latest Pelles C versions.
    Quote Originally Posted by Salem View Post
    You mean it's included as a crutch to help ancient programmers limp along without them having to relearn too much.

    Outside of your DOS world, your header file is meaningless.

  6. #6
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    I think it would take no more lines in straight C.
    And the point is?

  7. #7
    and the Hat of Guessing tabstop's Avatar
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    Quote Originally Posted by nonoob View Post
    I think it would take no more lines in straight C.
    I think the 1000+ lines vs. <100 lines was not C vs. C++, but 0 months experience vs. 5 months experience.

  8. #8
    Banned master5001's Avatar
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    Example:
    Code:
    #include <stdio.h>
    #include <math.h>
    
    float mul(float a, float b) { return a*b; }
    float add(float a, float b) { return a+b; }
    float sub(float a, float b) { return a-b; }
    float div(float a, float b) { return a*b; }
    float safe(float a, float b, float (*func)(float,float)) { return (func)?func(a,b):NAN; }
    
    int main(void)
    {
      float (*operators)(float,float)[] = {mul,add,0,sub,0,div}, a, b;
      char op;
    
      printf(">>");
      while(sscanf("&#37;f %c %f", &a, &op, &b) == 3)
      {
        if(op >= '*' && op <= '/')
          printf("%f\n", safe(a, b, operators[op-'*']));
        else
          fputs("Invalid entry! (Example: 5 * 5)", stderr);
        printf(">>");
      }
    
      return 0;
    }
    Happy, nonoob?

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