help with a grind

Hello

I got this grid working as you can se in the code bellow, but when i try to make some printf (or cout) to make it show some numbers i only get "0 0 1 1 2 2" displayed in a line. anyone know why and how i could make it the display the grid & Numbers like it should?

Code:

#include "stdafx.h"
#include <iostream> 
#include <ctime> 

using namespace std; 

int main() 
{
int grid[3][3]; // grid
int count = 1;

for(int i = 0; i < 3; i++){
     for(int n = 0; n < 3; n++){

          if(i == 2 && n == 2) break; // dont give out a number to square 9

          grid[i][n] = count; // give out a number to square 1-8
          count++;

		  cout << i << endl;

		  }
	
  }
return 0;
}

You should print out either count, or (more appropriately) grid[i][n], rather than the row number.

Originally Posted by tabstop

You should print out either count, or (more appropriately) grid[i][n], rather than the row number.

if i print out "grid[i][n]" the number become 1,2,3,4,5,6,7,8, and the same with count :/ it is supposed to look someting like this

http://www.imagefrog.net/out.php/i2912_4.jpg

That grid also contains the numbers 1 through 8. So?

(If you haven't noticed that you're printing a new line after every number, instead of after every row, you should do so now.)

Originally Posted by tabstop

That grid also contains the numbers 1 through 8. So?

(If you haven't noticed that you're printing a new line after every number, instead of after every row, you should do so now.)

ah sorry i actully did not notice that i printed one new line wich i now removed. How could i make it insteed print the numbers after every row isnteed ? :/

Instead of printing one endl per number, print one endl per row (you have one for loop that prints each row, so make sure that for loop only has one endl printed in it).