Thread: Finding divisors

Originally Posted by xbusterx

um like sum += num ?

Right.

Originally Posted by tabstop

Right.

Ya don't I don't know how to do that here since i is changing.

Originally Posted by xbusterx

Ya don't I don't know how to do that here since i is changing.

Since that's exactly what you want and need to happen, I fail to see how that's a problem.

(Or is your task not to add, but to count? In that case you would always add 1, since that's how people count.)

You have to use == to compare numbers, but yes, that's what we've been waiting for.

Originally Posted by tabstop

You have to use == to compare numbers, but yes, that's what we've been waiting for.

Code:

int sum =0; 
int n;

cout << enter number;
cin >> n; 

for (int i = 1 ; i < n ; i++ )

if ( n % i == 0 )
    sum += i

better lol?