please help me design a function!

This is a discussion on please help me design a function! within the C++ Programming forums, part of the General Programming Boards category; I am writing a program that converts arabic numbers to mayan numbers and vice versa. I got the converting arabic ...

  1. #1
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    Unhappy please help me design a function!

    I am writing a program that converts arabic numbers to mayan numbers and vice versa. I got the converting arabic numbers to mayan down perfect but I am really struggling to write a function converting mayan numbers to arabic. incase you don't know arabic numbers are regular 1 2 3 numbers and mayan numbers are represented by 0 . and -
    the conversion table looks like this

    0 0 | 5 - | 10 -- | 15 ---
    1 . | 6 .- | 11 .-- | 16 .---
    2 .. | 7 ..- | 12 ..-- | 17 ..---
    3 … | 8 …- | 13 …-- | 18 …---
    4 …. | 9 ….- | 14 ….-- | 19 ….---

    mayan numbers are base 20 and written backward so to Covert Mayan to Arabic you go like this:
    Mayan = ..-- .. ….--- 0 (12 2 19 0)
    Arabic = 0 * 20^0 + 19 * 20^1 + 2 * 20^2 + 12* 20^3 = 97180

    I read in the Mayan number as a char array and now have to create a function that converts the mayan number and returns an arabic number. This is what I have written so far but I am afraid I went in the completely wrong direction and there is a much easier way to solve this than I am attempting to. Any help would be great, Thanks!
    Code:
    	int counter=0;
    	int final=0;
    	int temp[20];
    	int temp2[50];
    	for(int q=0; q < 50; q++)
    		temp2[q] = 0;
    	for(int j=0; j < 20; j++)
    		temp[j] = 0;
    	for(int t=0; t < 25; t++)
    	{
    		for(int p=0; p < 25; p++)
    		{
    		if(MayanNumber[t] != '#') //MayanNumber array is declared as all #'s after the number
    		{
    			if(MayanNumber[t] != ' ')
    			{
    			switch(MayanNumber[t])
    			{
    				case '0':
    					temp[counter] = 0;
    					counter++;
    					break;
    				case '.':
    					temp[counter] = 1;
    					counter++;
    					break;
    				case '-':
    					temp[counter] = 5;
    					counter++;
    					break;
    			}
    			}
    			else
    			{
    				for(int k=0; k < counter; k++)
    					temp2[p] = temp2[p] + temp[k];
    			}
    		}
    		}
    	}
             //I havent written the part that tallys up every number yet but it will be assigned to 'final'
    	return final;
    Last edited by rainman39393; 10-01-2008 at 08:44 PM.

  2. #2
    Banned master5001's Avatar
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    >>mayan numbers are base 20 and written backward so to Covert Mayan to Arabic you go like this:

    Sounds like a job for strrev() and strtol(). Just put 20 for the third argument of strtol for a base 20 conversion.

  3. #3
    and the Hat of Guessing tabstop's Avatar
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    Quote Originally Posted by rainman39393 View Post
    mayan numbers are base 20 and written backward so to Covert Mayan to Arabic you go like this:
    Mayan = ..-- .. .--- 0 (12 2 19 0)
    Arabic = 0 * 20^0 + 19 * 20^1 + 2 * 20^2 + 12* 20^3 = 97180
    How is this written backwards? That's how we would normally write in a positional base system. (Largest exponent on the left, just like in base ten).

  4. #4
    Banned master5001's Avatar
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    Either way, strtol() handles arbitrary bases (within limitation). So you should be fine just converting strings strtol() can digest to mayan format and back. I had to do that for a barcoding system that I wrote a while back. I used a base 25 system that converted to and fro.

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