gotoxy and using arrows?

[SyntaxBubble]

I tried a code that had something like:


...

#define left 'K'
...

...

if(getch() == left)
{
gotoxy(x, y);
}

...

This code doesn't seem to work for me. What do I do?

[Prelude]

Here's an insanely simple example, use gotoxy and then redraw the menu. But use an algorithm instead of what I used for this toy program.

#include <iostream>
#include <conio.h>
using namespace std;

int main ( void )
{
  cout << "*" << " Choice 1" << endl;
  cout << "  Choice 2" << endl;
  cout << "  Choice 3" << endl;

  char ch;
  ch = getch();
  if ( ch == 'z' ) {
    gotoxy ( 0, 0 );
    cout << "  Choice 1" << endl;
    cout << "*" << " Choice 2" << endl;
    cout << "  Choice 3" << endl;
  }

  return 0;
}

[SyntaxBubble]

What if I wanted to get actual arrows, like the left or right key?

[Prelude]

That's system dependent, the ASCII character set doesn't specify the arrow keys, so you'll have to find out what the control commands are for them on your system. Windows programs have functions to test the value of the keys, try MSDN if you use Windows.

-Prelude

[samGwilliam]

To get the actual keys, you need to get the scan codes. Look at the attatchment, this only works in DOS.

[samGwilliam]

Oh, and you must add this:

oldKeybInt = getvect (KEYB_INT);		// Re-direct ISR.
setvect (KEYB_INT, newKeybInt);

at the beginning of your main and:

setvect (KEYB_INT, oldKeybInt);		// Replace old keyboard interrupt.

at the end.

[SlimDady]

I did somthing like that in a project a while back.. used the up and down keys to move a line.. It was a selectable menue where I changed the textbackground.

U have to know what key value the arrow returns..