Thread: a C++ question

  1. #16
    Registered User
    Join Date
    Oct 2001
    Posts
    101
    Thx a lot!!!

    I worte something like this for right shift...

    int shift_right(int num)
    {
    int i = log10(num)+1; //Get number of digits
    int c = num/10; //Get far right digit
    int d = num-(c*10);
    //Add previous far right digit onto left
    num = c + (d*pow(10,i-1));
    return num;

    }


    I've checked it... no bugs... but... just want someone to give me some comments of it......


    Thx!!
    Last edited by DramaKing; 02-12-2002 at 07:13 PM.

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