% illegal error?

Hi everyone,
I am having this error:

Code:

error C2296: '%' : illegal, left operand has type 'int *'

What does this mean?

Code:

//Write a function countEven(int*, int) which receives 
//an integer array and its size, and returns the number 
//of even numbers in the array.

#include <iostream>
#include <cstdlib>
#include <ctime>
using namespace std;

int countEven(int* array, int n)
{
	for (int i = 0; i < n; ++i)
	{
		if (array % 2 == 0)   // <----ERROR!
			cout << *array << " ";
		else
			continue;
	}
	return *array;
}

int main()
{
	int el = 0;
	cout << "Enter the number of array elements: ";
	cin >> el;

	int* Array = new int[el]; //dynamic memory allocated
	
	cout << "Enter your array values: " << endl;
	for (int i = 0; i < el; ++i)
	{
		cout << "[" << i << "]: ";
		cin >> *(Array + i);
	}
	cout << "Your array values are: {";
	for (int i = 0; i < el; ++i)
	{
		cout << *(Array + i) << ",";
	}
	cout << "}" << endl;

	cout << "Your even number elements are: {";
	countEven(Array, el);
	cout << "}" << endl;

	delete Array;
	Array = 0;
}

Thanks!

What does this mean?

It means that you are trying to compute the remainder of dividing an address by 2. You actually want to compute the remainder of dividing the integer at that address by 2 (or otherwise determine if the integer is even or odd).

Thanks for the quick reply and a very direct answer, laserlight..
I modified it, however, it only outputs the first even element, and it outputs it three times. Why do you think that is?
Thanks..

Code:

int countEven(int* array, int n)
{
	for (int i = 0; i < n; ++i)
	{
		if (array[i] % 2 == 0)
			cout << *array << " ";
		else
			continue;
	}
	return *array;
}

int main()
{
	int el = 0;
	cout << "Enter the number of array elements: ";
	cin >> el;

	int* Array = new int[el]; //dynamic memory allocated
	
	cout << "Enter your array values: " << endl;
	for (int i = 0; i < el; ++i)
	{
		cout << "[" << i << "]: ";
		cin >> *(Array + i);
	}
	cout << "Your array values are: {";
	for (int i = 0; i < el; ++i)
	{
		cout << *(Array + i) << ",";
	}
	cout << "}" << endl;

	cout << "Your even number elements are: {";
	countEven(Array, el);
	cout << "}" << endl;

	delete Array;
	Array = 0;
}

Code:

		if (array[i] % 2 == 0)
			cout << *array << " ";

The error is in the above. Can you spot it?

--
Mats

I modified it, however, it only outputs the first even element, and it outputs it three times. Why do you think that is?

Notice that you are printing *array instead of array[i]. Note also that you are returning *array.

By the way, the else continue is redundant. Oh, and remember to match new[] with delete[], not delete.

Code:

int countEven(int* array, int n)
{
...
	return *array;
}

Is the *array actually the number of even numbers?

--
Mats

Thanks, laserlight and matsp..
I am still a little bit confused when it comes to pointers and actually, references too. Thanks for explaining the errors, laserlight. You're a fine teacher! Thanks!

Hi matsp,
Actually no, I got it all wrong, it was supposed to be the even elements. Pointer syntax still confuse me, thanks for your help..