trying to display two digits

How do i display cout << 1; in two digits '01'

One option is to use std::setw and std::setfill from <iomanip>, e.g.,

Code:

cout << setw(2) << setfill('0') << 1;

Code:

 #include <iomanip>
std::cout << std::setw(2) << std::setfill('0') << 1;

QuantumPete

Originally Posted by QuantumPete

Code:

 #include <iomanip>
std::cout << std::setw(2) << std::setfill('0') << 1;

QuantumPete

for some reason it puts the zero after the digit 1 becomes 10 ..

Code:

		cout  << left << setw(2) << setfill('0') << iter->getIssueDate().getDay()  << " / " << left << setw(2) 
			 << iter->getIssueDate().getMonth()  << " / " << left << setw(6) << iter->getIssueDate().getYear();
		cout  << iter->getIssueDate().getHour() << ":" << iter->getIssueDate().getMinute();

for some reason it puts the zero after the digit 1 becomes 10 ..

Perhaps you set the justification to left in some earlier portion of the code, so just set it to right, e.g.,

Code:

cout << setw(2) << setfill('0') << right << 1;

Originally Posted by laserlight

Perhaps you set the justification to left in some earlier portion of the code, so just set it to right, e.g.,

Code:

cout << setw(2) << setfill('0') << right << 1;

I thought as so, but i need it left..

Code:

	// Date [01/01/2008]
	cout << left << setw(2) << setfill('0') << iter->getIssueDate().getDay();
	cout << " / " << left << setw(2) << iter->getIssueDate().getMonth();
	cout << " / " << left << setw(6) << iter->getIssueDate().getYear();

	// Clock [12:45]
	cout << iter->getIssueDate().getHour() << ":" << iter->getIssueDate().getMinute();

Also, why is this 0 inserted to all the following couts following it, how do i enforce it to only one variable/value ?

I thought as so, but i need it left..

For the printing of this date, set the justification to right, then change it back to left afterwards.

Also, why is this 0 inserted to all the following couts following it, how do i enforce it to only one variable/value ?

You can setfill(' ') after you are done. More generally when you are overloading operator<<, save the format flags before you begin changing them, then restore them after you are done.

Originally Posted by laserlight

For the printing of this date, set the justification to right, then change it back to left afterwards.


You can setfill(' ') after you are done. More generally when you are overloading operator<<, save the format flags before you begin changing them, then restore them after you are done.

Just checking

Code:

cout << "[" << right << setw(2) << setfill('0') <<  left <<  iter->getIssueDate().getDay() ;
cout << setfill(' ');

No! this doesn't work .. Still puts zero's after

You could also just print the year followed by two spaces (instead of the year with width 6), then the time and finally set the alignment and fill character back just once.

But in any case, formatted output is usually simpler with format strings, e.g with boost::format

Code:

std::cout << boost::format("&#37;02d/%02d/%d  %02d:%02d") % 1 % 8 % 1946 % 14 % 8 << '\n';

Originally Posted by anon

You could also just print the year followed by two spaces (instead of the year with width 6), then the time and finally set the alignment and fill character back just once.

But in any case, formatted output is usually simpler with format strings, e.g with boost::format

Code:

std::cout << boost::format("%02d/%02d/%d  %02d:%02d") % 1 % 8 % 1946 % 14 % 8 << '\n';

Cool, looks more a c style , printf() .. thanx

No! this doesn't work .. Still puts zero's after

That's because you set the justification back to left before you actually print the number.

Another option, which may make your entire date-printing easier to handle, would be to have a "tostring" function (and a "fromstring"?) in your Date class, that produces a std::string.

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Mats