Thread: problem initializing function pointer

I am trying to create a pointer that would point to Out32 function in inpout32.dll.
and the following code does not work, can someone give me more insight about
why it doesnt work?

Code:

#include <iostream>
#include <windows.h>
     
int main()
{
   HINSTANCE Dllload = LoadLibrary("inpout32.dll");
 
   if (Dllload)
   {
           
     void (*outport)(short adress, short value) = GetProcAddres(Dllload, "Out32");
     std::cout<<"success";
     std::cin.get();
   }
   else
   { 
       std::cout<<"inpout32.dll failed to load";
       std::cin.get();
   }
}

it loads inpout32.dll ok, but it has problem with that function pointer initialization
compiler has this to say about my code:
In function `int main()':
invalid conversion from `int (*)()' to `void (*)(short int, short int)'

but the code with typedef works,

Code:

#include <iostream>
#include <windows.h>

typedef void (*outportpoint)(short adress,short value);     
int main()
{
   HINSTANCE Dllload = LoadLibrary("inpout32.dll");
 
   if (Dllload)
   {
            outportpoint outport;
            outport = (outportpoint) GetProcAddress(Dllload, "Out32");
            std::cout<<"success";
            std::cin.get();
   }
   else
   { 
       std::cout<<"inpout32.dll failed to load";
       std::cin.get();
   }
}

isn't typedef used here to make creation of multiple pointers easier insted of declaring each new pointer?

ok, but if you try
void (*outport)(short adress, short value) = (void)GetProcAddres(Dllload, "Out32");
that doesn't work niether. Is there any other way other than typedef?

You have to cast it to the type on the left, which is (void (*)(short, short)), not some other random type.

Code:

   if (Dllload)
   {
           
     void (*outport)(short adress, short value) = (void (*)(short, short))GetProcAddres(Dllload, "Out32");
     std::cout<<"success";
     std::cin.get();
   }

Yep that did the trick!
But this leads me to another bunch of questions.

Doesn't GetProcAddress function give you just the adress of Out32 ?

Why do we need to typecast if the pointer is of type void pointer (short,short) and if I understand correctly Out32 is void Out32(short,short) ?

What is so special about GetProcAddress function?

The problem is that GetProcAddress is not special at all: functions are only allowed to return one type of thing, and it appears that MS has chosen the generic C "function returning int with no given arguments" (which a non-prototyped function is assumed to be in C). C++ is more strict about types than that, though.