Getting correct output

I'm fairly new to programming in general and have just started to learn C++. So as a small project to test what I know and just see what I can accomplish on my own I decided to make a simple calculator program that will compute simple addition, subtraction, multiplication and division and output the result. However, I can't figure out a way to make this program output a remainder for division problems that would have one.

Code:

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#include <iostream>

using namespace std;

int Operate(int numerouno, char operation, int numerodos); //Declares function 'Operate'


int main()
{

    //VARIABLES
    int num1;
    char affirm;
    int num2;
    char affirm2;
    char operation;
    int result;
    char restart;

    int loop;
    loop = 1;


    //INTRODUCTION
    cout<<"Welcome to the Basic Calculator. In this program you will be able to add, \nsubtract, multiply or divide two numbers.\n" << endl;
    //PROMPT FOR FIRST VALUE

    beginagain://Restart point if user wants to re-use program at the end.
    cout<<"What is your first number going to be?\n" << endl;
    /*goto command from Line 32*/ onenum:cin >> num1;

    //Checking for accuracy on First Number
    cout<<"\nAre you sure you want to use " << num1 << " as your first number?\nPress 'y' for yes and 'n' for no.\n" << endl;
    cin >> affirm;
    cout<<endl;

    //If User says number is not correct prompts them to re-enter it by using goto.
        while (affirm == 'n')
        {
            cout<<"Well then re-enter your first number, please.\n" << endl;
            goto onenum; //On line 17
        }

  //After "affirm" is 'y' - Program continues and user is informed.
    cout<<"Ok! First number registered.\n"<<endl;


    //Prompts for second number.
    cout<<"What do you want your second number to be?\n" << endl;
    twonum:cin >> num2;

    //Checks for accuracy of second number.
    cout<<"\nAre you sure you want to use " << num2 << " as your second number?\nPress 'y' for yes and 'n' for no.\n" << endl;
    cin >> affirm2;

        //User can revise their second number if answer to above question is "n"
        while (affirm2 == 'n')
        {
            cout<<"\nOh, then please re-enter your second number.\n" << endl;
            goto twonum; //On Line 41
        }

    //After affirm2 = y, program continues.
    cout<<"\nOk! Now that we have both of your chosen numbers, what would you like to do withthem?\n"<<endl;
    //Gives instructions on what to input for desired operation.
    cout<<"+ for Addition\n- for Subtraction\n* for Multiplication\n/ for Division\n" << endl;
    cin>>operation;

    //Gets result by calling function Operate
    result = Operate(num1, operation, num2);



    //prints out the expression and the answer
    cout<<"\n"<<num1<<operation<<num2<<"="<<result<<endl;
    cout<<"WARNING: If dividing and there is a remainder, the remainder will not show."<<endl;


    cout<<"\n\n\nWould you like to go back to the beginning of the Calculator?\n'Y' for yes or 'N' for no."<<endl;
    cin>>restart;
        if (restart=='Y')
            goto beginagain;
        else
            loop=0;
}


//FUNCTIONS

int Operate(int num1, char operation, int num2)
{
    if (operation=='+')
        return num1+num2;
    else if (operation=='-')
        return num1-num2;
    else if (operation=='*')
        return num1*num2;
    else if (operation=='/')
        return num1/num2;
    else cout<<"You suck."<<endl;
}

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That's the code for a working program that does all the right functions. I'm just not sure about how to make it output a remainder value for division. I don't care if it outputs a '0' remainder for addition subtraction and multiplication as well, but I would like it to output a correct remainder for the division.

The integer divide functionality in C++ (and most other languages, such as C, Pascal, Fortran, etc) gives you the integer part of the result. If you want to see what the remainder is, you can (cheat a bit [1] and) use the % operator.


[1] To correctly calculate the remainder, you do

Code:

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r = x - (x / y) * y;

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Mats

Since you've managed to use one while loop, there's no reason to fill the code with goto statements.

Thank you matsp. I got an idea after you posted that and was able to fix my remainder problem. Salem, thanks for the idea, I'm still a little shaky on while loops (a problem that hopefully gets solved with a little practice. Thanks to both of you for your help.