I'm fairly new to programming in general and have just started to learn C++. So as a small project to test what I know and just see what I can accomplish on my own I decided to make a simple calculator program that will compute simple addition, subtraction, multiplication and division and output the result. However, I can't figure out a way to make this program output a remainder for division problems that would have one.

That's the code for a working program that does all the right functions. I'm just not sure about how to make it output a remainder value for division. I don't care if it outputs a '0' remainder for addition subtraction and multiplication as well, but I would like it to output a correct remainder for the division.Code:`#include <iostream>`

using namespace std;

int Operate(int numerouno, char operation, int numerodos); //Declares function 'Operate'

int main()

{

//VARIABLES

int num1;

char affirm;

int num2;

char affirm2;

char operation;

int result;

char restart;

int loop;

loop = 1;

//INTRODUCTION

cout<<"Welcome to the Basic Calculator. In this program you will be able to add, \nsubtract, multiply or divide two numbers.\n" << endl;

//PROMPT FOR FIRST VALUE

beginagain://Restart point if user wants to re-use program at the end.

cout<<"What is your first number going to be?\n" << endl;

/*goto command from Line 32*/ onenum:cin >> num1;

//Checking for accuracy on First Number

cout<<"\nAre you sure you want to use " << num1 << " as your first number?\nPress 'y' for yes and 'n' for no.\n" << endl;

cin >> affirm;

cout<<endl;

//If User says number is not correct prompts them to re-enter it by using goto.

while (affirm == 'n')

{

cout<<"Well then re-enter your first number, please.\n" << endl;

goto onenum; //On line 17

}

//After "affirm" is 'y' - Program continues and user is informed.

cout<<"Ok! First number registered.\n"<<endl;

//Prompts for second number.

cout<<"What do you want your second number to be?\n" << endl;

twonum:cin >> num2;

//Checks for accuracy of second number.

cout<<"\nAre you sure you want to use " << num2 << " as your second number?\nPress 'y' for yes and 'n' for no.\n" << endl;

cin >> affirm2;

//User can revise their second number if answer to above question is "n"

while (affirm2 == 'n')

{

cout<<"\nOh, then please re-enter your second number.\n" << endl;

goto twonum; //On Line 41

}

//After affirm2 = y, program continues.

cout<<"\nOk! Now that we have both of your chosen numbers, what would you like to do withthem?\n"<<endl;

//Gives instructions on what to input for desired operation.

cout<<"+ for Addition\n- for Subtraction\n* for Multiplication\n/ for Division\n" << endl;

cin>>operation;

//Gets result by calling function Operate

result = Operate(num1, operation, num2);

//prints out the expression and the answer

cout<<"\n"<<num1<<operation<<num2<<"="<<result<<endl;

cout<<"WARNING: If dividing and there is a remainder, the remainder will not show."<<endl;

cout<<"\n\n\nWould you like to go back to the beginning of the Calculator?\n'Y' for yes or 'N' for no."<<endl;

cin>>restart;

if (restart=='Y')

goto beginagain;

else

loop=0;

}

//FUNCTIONS

int Operate(int num1, char operation, int num2)

{

if (operation=='+')

return num1+num2;

else if (operation=='-')

return num1-num2;

else if (operation=='*')

return num1*num2;

else if (operation=='/')

return num1/num2;

else cout<<"You suck."<<endl;

}