Hi,

Here is a method inside a string returning function:

Code:

string computeSin(argument 1, argument 2)
{
if ( strcmp(icmop->icmo_addl_infop->retval_str, "USA") == 0 )
{
string newIsin = (string)"US" + icmop->icmo_tranche_cusips[trancheNum];
int d1, d2, sum, multiply, i;
for (sum = 0, multiply = 1, i = 10; i > -1; --i) {
switch (i) {
case 0:
case 1:
if (isupper(newIsin[i]))
d1 = newIsin[i] - 'A' + 10;
else
return 0;
break;
default:
if (isupper(newIsin[i]))
d1 = newIsin[i] - 'A' + 10;
else if (isdigit(newIsin[i]))
d1 = newIsin[i] - '0';
else
return 0;
break;
}
if (d1 < 10) {
d1 *= (multiply ? 2 : 1);
multiply = !multiply;
} else {
d2 = d1 / 10;
d1 %= 10;
d1 *= (multiply ? 2 : 1);
d2 *= (multiply ? 1 : 2);
sum += (d2 % 10) + (d2 / 10);
}
sum += (d1 % 10) + (d1 / 10);
}
sum %= 10;
sum = 10 - sum;
sum %= 10;
std::stringstream isinSs;
isinSs << newIsin << sum;
const std::string &checkedIsin = isinSs.str();
return checkedIsin;
}
return argument 2;
}//end of string method

My Question:

If in the switch statement section of this code I reach return 0 (appears twice: once in case 1 and other in default), would I be taken out of this computeSin method or would I keep looping till the for loop finishes?

Normally, a return statement takes you out of a function but in this case if I reach return 0 which is in a switch statement that will keep running till the for loop ends, would I exit the whole method?

Thanks.