pointers

This is a discussion on pointers within the C++ Programming forums, part of the General Programming Boards category; int i=24; int* poin; *point=i; cout<<*poin; cout<<poin; cout<<&i; why pion and &i does not show the same results as poin ...

  1. #1
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    pointers

    int i=24;
    int* poin;
    *point=i;
    cout<<*poin;
    cout<<poin;
    cout<<&i;
    why pion and &i does not show the same results as poin contain the address of i and &i means adress of i

  2. #2
    and the Hat of Guessing tabstop's Avatar
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    Why do you think poin contains the address of i? If you had done poin = &i, then yes. Otherwise, no.

    int *poin defines a pointer, but it doesn't point to anywhere in particular. So *poin = i puts the value of i in the memory address pointed to by poin (wherever it is).

  3. #3
    C++まいる!Cをこわせ! Elysia's Avatar
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    I'm quite surprised you don't get a crash.
    Quote Originally Posted by Adak View Post
    io.h certainly IS included in some modern compilers. It is no longer part of the standard for C, but it is nevertheless, included in the very latest Pelles C versions.
    Quote Originally Posted by Salem View Post
    You mean it's included as a crutch to help ancient programmers limp along without them having to relearn too much.

    Outside of your DOS world, your header file is meaningless.

  4. #4
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    you have your referencing/dereferencing operators backwards.

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